All categories

2 years ago

Find the area of a regular octagon with side length 4 cm.

Mathematics

1 answer:

Degger [83]2 years ago

4 0

A = side^2 * (2 + 2sqrt2))
A = 4^2 * (2 + 2sqrt2))
A = 77.25 cm^2

You might be interested in

How do you solve 2x^2+x=-1?

Olin [163]

Answer:

x = 0.2

Step-by-step explanation:

2x^2+x=-1

4x + x = -1

5x = -1

divide by 5

5x/5 = -1/5

x = 0.2

3 0

3 years ago

How do you solve for 4y+20=5x

Dima020 [189]

You cant because there are 2 different variables

hope this helps, have a great day

3 0

3 years ago

Read 2 more answers

Use the functions f(x) and g(x) to answer the question. F(x)=x²-16; g(x)=x+4

AnnZ [28]

(x^2) - 16 / x+4 = (x-4)(x+4) / (x+4) = x-4, x not equal to -4

D is the answer.

7 0

3 years ago

The time it takes you to get to campus varies inversely as your driving rate. averaging 20 miles per hour in terrible traffic,

Korvikt [17]

Given that the time taken to get to campus is inversely proportional to driving rate, let the time be t and rate be r, thus the function will be written as:'
t=k/r
where
k is the constant of proportionality given by:
k=tr
when r=20 mph, t=1.25 hrs
thus
k=20×1.25
k=25 miles
thus the formula is:
t=25/r
when r=55 mph, the value of t will be:
t=25/55
t=5/11 hours

3 0

3 years ago

As.

Natalka [10]

9514 1404 393

Answer:

4/13 h ≈ 0.308 h
22 9/13 km ≈ 22.7 km

Step-by-step explanation:

Mary and Amaruk are starting 35 -15 = 20 km apart. Their closing speed is 40 +25 = 65 km/h. The time it will take to close the gap between them is ...

t = (20 km)/(65 km/h) = 20/65 h = 4/13 h ≈ 0.308 h

They will pass each other after 4/13 hours, about 18 minutes 28 seconds.

In that time, Mary will have increased her distance from Hall Beach by ...

d = (4/13 h)(25 km/h) = 100/13 km = 7 9/13 km

Her distance from Hall Beach when she passes Amaruk will be ...

15 km + 7 9/13 km = 22 9/13 km ≈ 22.7 km . . . . . distance from Hall Beach

6 0

3 years ago