All categories

4 years ago

Can you solve x and y please

Mathematics

1 answer:

Radda [10]4 years ago

8 0

Answer:

x = 12
y = 125

Step-by-step explanation:

The upper and lower angles are vertical angles, so congruent:

(5x -5)° = 55°

x - 1 = 11 . . . . . . . divide by 5°

x = 12

_____

The 55° angle and y° are a linear pair, so are supplementary.

y° = 180° -55°

y = 125 . . . . . . . simplify, divide by °

You might be interested in

3/8-1/3<br><br><br><br> I rly need help and FAST

elixir [45]

Answer:

Step-by-step explanation:

1/24

6 0

3 years ago

Residents in a city are charged for water usage every three months. The water bill is computed from a common fee, along with the

vampirchik [111]

Answer:

Step-by-step explanation:

Just checked this is correct

6 0

3 years ago

Read 2 more answers

Use mental math to find the product of 3×58

MrRissso [65]

Answer:

105

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

A box with a square base and an open top is being constructed out of A cm2 of material. If the volume of the box is to be maximi

viktelen [127]

Answer:

Side length = $\sqrt{\frac{A}{3} }$ cm , Height = $\frac{1}{2} \sqrt{\frac{A}{3} }$ cm , Volume = $\frac{A\sqrt{A}}{6\sqrt{3} }$ cm³

Step-by-step explanation:

Assume

Side length of base = x

Height of box = y

total material required to construct box = A ( given in question)

So it can be written as

A = x² + 4xy

4xy = A - x²

$y = \frac{A - x^{2} }{4x}$

Volume of box = Area x height

V = x² ₓ y

V = x² ₓ ( $\frac{A - x^{2} }{4x}$ )

V = $\frac{Ax - x^{3} }{4}$

To find max volume put V' = 0

So taking derivative equation becomes

$\frac{A - 3 x^{2} }{4} = 0$

A = 3 $x^{2}$

$x^{2}$ = $\frac{A}{3}$

x = $\sqrt{\frac{A}{3\\} }$

put value of x in equation 1

y = $\frac{A - \frac{A}{3} }{4\sqrt{\frac{A}{3} } }$

y = $\frac{2 \sqrt{\frac{A}{3} } }{4 \sqrt{\frac{A}{3} } }$

y = $\frac{1}{2} \sqrt{\frac{A}{3} }$

So the volume will be

V = $x^{2}$ × y

Put values of x and y from equation 2 & 3

V = $\frac{A}{3} (\frac{1}{2} \sqrt{\frac{A}{3} } )$

V = $\frac{A\sqrt{A}}{6\sqrt{3} }$

8 0

4 years ago

The following is a set of hypotheses, some information from one or more samples, and a standard error from a randomization distr

Tanya [424]

Complete Question

The following is a set of hypotheses, some information from one or more samples, and a standard error from a randomization distribution. Test $H_o : p = 0.28$ vs $H a : p < 0.28$ when the sample has n 900 , and $\^ p = 0.216$ with $SE= 0.01$ . Find the value of the standardized z -test statistic. Round your answer to two decimal places.