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aalyn [17]
3 years ago
13

What is the remainder when 2x^3+3x^2+x+1 is divided by x+3

Mathematics
1 answer:
ExtremeBDS [4]3 years ago
4 0
2x^3 + 3x^2 + x + 1
=2x^3 + 3x^2 + 3x^2 - 3x^2 + x + 1
=2x^3 + 6x^2 - 3x^2 + x + 1
=2(x^3 + 3x^2) - 3x^2 + x + 1
=2x^2*(x+3) - 3x^2 -9x + 9x + x +1
=2x^2*(x+3) - 3x(x+3) + 10x +1
=2x^2*(x+3) - 3x(x+3) + 10x + 30 - 30 +1
=2x^2*(x+3) - 3x(x+3) +10(x+3) -29

The first three terms can be divided by (x+3) evenly so the remainder is -29
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Answer:

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Step-by-step explanation:

It is easy

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6 0
3 years ago
PLEASEEEE HELP I NEED A ANSWER ASAP!!!!!!!
Licemer1 [7]

Answer:

520 - 303.93 - (10.99 * 4) - 25.25 - 73.43x ≥ 0

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1) Parentheses

520 - 303.93 - 43.96 - 25.25 - 73.43x ≥ 0

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2) Combine like terms

146.86 - 73.43x ≥ 0

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3) Get the variable term alone

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** dividing by a negative number, the inequality sign flips **

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x ≤ 2

8 0
2 years ago
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evablogger [386]
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4 0
4 years ago
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Step-by-step explanation:

7 0
3 years ago
HELP!!
maksim [4K]
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4 years ago
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