Answer:
A triangle and an octagon
Step-by-step explanation:
Let me know if either one of them is wrong
Given points A(−2,0), B(−5,3), C(−9,−1), P(7,6), Q(4,0), and R(−4,4), which of the following proves that △ABC~△PQR?
UNO [17]
Based on the SSS similarity theorem, △ABC ~ △PQR because AB/PQ = BC/QR = CA/RP = √2/√5 = √10/5 (option D).
<h3>The SSS Similarity Theorem</h3>
Two triangles having three pairs of sides that are proportional can be proven to be similar by the SSS similarity theorem.
If the triangle ABC and triangle PQR are similar, their corresponding sides will be proportional, meaning that: AB/PQ = BC/QR = CA/RP.
Therefore, using the distance formula,
, the sides of each triangle is found.
Therefore, it shows that:
AB/PQ = BC/QR = CA/RP = √2/√5 = √10/5
Therefore, based on the SSS similarity theorem, △ABC ~ △PQR because AB/PQ = BC/QR = CA/RP = √2/√5 = √10/5 (option D).
Learn more about the SSS similarity theorem on:
brainly.com/question/4163594
12:36 you have to look at closely I made a mistake for not looking at the word correctly
2)Perimeter=28 rounded to 30. Area=48 rounded up to 50.