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devlian [24]
3 years ago
13

2log50+2log2 sederhanakan dengan caranya

Mathematics
1 answer:
Jet001 [13]3 years ago
4 0

Answer:

4

Step-by-step explanation:

log(50×50)×log(2×2)

log (2500)×log(4)

log(2500×4)

log(10000)

log(10^4)

=4

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If <img src="https://tex.z-dn.net/?f=log_%7B2%7D" id="TexFormula1" title="log_{2}" alt="log_{2}" align="absmiddle" class="latex-
12345 [234]

Answer:

The answer is (1/2)z - x - 3y

Step-by-step explanation:

∵ log_{2}P=x

∵ log_{2}Q=y

∵ log_{2}R=z

∵ log_{2}\frac{R^{\frac{1}{2}}}{(P)(Q^{3})}

∴ log_{2}(R)^{\frac{1}{2}}-log_{2}P-log_{2}(Q^{3})

∴ \frac{1}{2}log_{2}R-log_{2}P-3log_{2}Q

∴ \frac{1}{2}z-x-3y

3 0
4 years ago
What remainder is represented by the synthetic division below?
Goryan [66]

The remainder represented by synthetic division is -5.

<h3>What is synthetic division?</h3>

Synthetic division can be defined as a simplified way of dividing a polynomial with another polynomial equation of degree 1.

Given

A vertical line and a horizontal line combine to make an L shape.

There are two rows of entries within the shape.

Row 1 has entries 2, 10, 1, 5.

Row 2 has entries blank, -10, 0, -5.

Entry -5 is on the outside to the left of the shape. The entry represents the zero of the divisor. This entry to the variable (assume the variable is x) is;

x + 5 = 0

x = -5

Hence, the divisor of the synthetic division is -5.

To know more about synthetic division click the link given below.

brainly.com/question/6789595

#SPJ1

6 0
2 years ago
Please do one for 3-5 and one for 6-8 i will give brainliest
scoray [572]

Answer:

Use the arithmetic formal

Step-by-step explanation:

an = d (n - 1) + c

4 0
3 years ago
PLEASE GEOMETRY HELP WILL MARK BRAINLIEST!!!
DaniilM [7]

Answer:

(3) ABCE hope this is correct

7 0
3 years ago
Read 2 more answers
The life in hours of a biomedical device under development in the laboratory is known to be approximately normally distributed.
bearhunter [10]

Answer:

Kindly check explanation

Step-by-step explanation:

H0 : μ = 5500

H1 : μ > 5500

The test statistic assume normal distribution :

Test statistic :

(Xbar - μ) ÷ s/sqrt(n)

(5625.1 - 5500) ÷ 226.1/sqrt(15) = 2.1429 = 2.143

Pvalue from test statistic :

The Pvalue obtained using the calculator at df = 15 - 1 = 14 is 0.025083

α = 0.05

Since ;

Pvalue < α

0.025083 < 0.05 ; Reject H0

The confidence interval :

Xbar ± Tcritical * s/sqrt(n)

Tcritical at 95% = 1.761 ;

margin of error = 1.761 * 226.1/sqrt(15) = 102.805

Lower boundary : (5625.1 - 102.805) = 5522.295

(5522.295 ; ∞)

The hypothesized mean does not occur within the constructed confidence boundary. HENCE, there is significant eveidbce to support the claim that the true mean life of a biomedical device is greater than 5500

4 0
3 years ago
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