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garik1379 [7]
3 years ago
13

How do you solve it​

Mathematics
1 answer:
eduard3 years ago
6 0

Answer:

How do you solve what?

Step-by-step explanation:

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I need help on the first and last one, there the fill in the blank ones
PtichkaEL [24]

Answer:

The sample space (S) that consists of all elements is:

S = {red, red, red, red, white, white, white, white, blue, blue, blue, blue}.

The number of ways (N) that the four letters F, A, I, R can be arranged is:

N = 4 x 3 x 2 x 1 = 24

Hope this helps!

4 0
3 years ago
The perimeter of a square is represented by 4x − 16. What is the length of a side of this square?
NikAS [45]

Answer:

(x-4)

Step-by-step explanation:

Since a square has 4 equal sides, the perimeter of a square is 4 times one of the sides (which is equal to adding all the sides together). So:

Perimeter = 4(a side) = 4x-16

a side = (4x-16)/4 = (x-4)

7 0
3 years ago
Read 2 more answers
PLZZZZZZ HELPPPPP
Makovka662 [10]

Answer:

(D)                                            

Step-by-step explanation:

The graph shows the arm span lengths of the students, clearly we can see that the most of the students have arm span length in the initial points of the length.

Median = Middle frequency of the data. Here, median will be the length in the middle.

Mode = Most frequently occurring number in the data. Here the mode will be the length which most of the students has.

Clearly, most of the student has the length in the initial inches while the median will be in the middle.

Hence, mode will be less than the median.  

8 0
3 years ago
Read 2 more answers
If 90 is 80 percent of the value what is the value
OLga [1]
If 90 is 80% of the whole value, then 1/4 of 90 added to 90 will be the value, because 1/4 of 80% (which is 20%) added to 80% will give us 100%

So,
90/4=12.5
90 + 12.5=102.5

At least, that's my take on it
5 0
3 years ago
The x- intercepts of a parabola are (0,-6) and (0,4). The parabola crosses the y- axis at -120. Lucas said that an equation for
astraxan [27]

Given:

The x- intercepts of a parabola are (0,-6) and (0,4).

The parabola crosses the y- axis at -120.

Lucas said that an equation for the parabola is y=5x^2+10x-120 and that the coordinates of the vertex are (-1, -125).

To find:

Whether Lucas is correct or not.

Solution:

The x- intercepts of a parabola are (0,-6) and (0,4). It means (x+6) and (x-4) are the factors of the equation of the parabola.

y=a(x+6)(x-4)             ...(i)

The parabola crosses the y- axis at -120. It means the equation of the parabola must be true for (0,-120).

-120=a(0+6)(0-4)

-120=a(6)(-4)

-120=-24a

Divide both sides by -24.

\dfrac{-120}{-24}=a

5=a

Substituting a=5 in (i), we get

y=5(x+6)(x-4)

y=5(x^2+6x-4x-24)

y=5(x^2+2x-24)

y=5x^2+10x-120

So, the equation of the parabola is y=5x^2+10x-120.

The vertex of a parabola f(x)=ax^2+bx+c is:

Vertex=\left(-\dfrac{b}{2a},f(-\dfrac{b}{2a})\right)

In the equation of the parabola, a=5,b=10,c=-120.

-\dfrac{b}{2a}=-\dfrac{10}{2(5)}

-\dfrac{b}{2a}=-\dfrac{10}{10}

-\dfrac{b}{2a}=-1

Putting x=-1 in the equation of the parabola, we get

y=5(-1)^2+10(-1)-120

y=5-10-120

y=-125

So, the vertex of the parabola is at point (-1,-125).

Therefore, Lucas is correct.

5 0
3 years ago
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