Answer:
For 32 bits Instruction Format:
OPCODE DR SR1 SR2 Unused bits
a) Minimum number of bits required to represent the OPCODE = 3 bits
There are 8 opcodes. Patterns required for these opcodes must be unique. For this purpose, take log base 2 of 8 and then ceil the result.
Ceil (log2 (8)) = 3
b) Minimum number of bits For Destination Register(DR) = 4 bits
There are 10 registers. For unique register values take log base 2 of 10 and then ceil the value. 4 bits are required for each register. Hence, DR, SR1 and SR2 all require 12 bits in all.
Ceil (log2 (10)) = 4
c) Maximum number of UNUSED bits in Instruction encoding = 17 bits
Total number of bits used = bits used for registers + bits used for OPCODE
= 12 + 3 = 15
Total number of bits for instruction format = 32
Maximum No. of Unused bits = 32 – 15 = 17 bits
OPCODE DR SR1 SR2 Unused bits
3 bits 4 bits 4 bits 4 bits 17 bits
Answer:
The republicans storming the capitol
Explanation:
Answer:
The program to this question can be given as:
Program:
factorial=1 #declare a variable.
number=int(input("Enter a positive integer:")) #input a number.
while (number>0): #loop
factorial= factorial*number # holding value in factorial variable
number=number-1
print('=',factorial) #print value.
Output:
Enter a positive integer:6
= 720
Explanation:
The description of the above python program can be given as:
- In the above program firstly we define a variable that is "factorial". In this variable, we assign a value that is 1 and it is used to calculate the factorial value.
- We define a variable "number". The number variable is used to take input from the user.
- Then we define a loop in the loop we calculate the factorial and hold the value in the factorial value in the last we print the value.