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Schach [20]
3 years ago
9

Solve the equation for W and L

Mathematics
1 answer:
Roman55 [17]3 years ago
4 0

Answer:

Step-by-step explanation:

Cross multiply and get:

\sqrt{7}L = 5w

L = 5w/\sqrt{7}

W = \sqrt{7}L/5

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Find the area of a circle whose circumference measures 28 centimeters.
vagabundo [1.1K]
Assume the radius is R.

2*pi*R = 28 -> R = 14/pi

So the area will be pi*R^2 = 196/pi
7 0
3 years ago
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The reacttimes data set has 50 observations of human reaction times to a physical stimulus. The reaction times are named times a
scoundrel [369]

Solution: The formula for mean is:

Mean=\frac{\sum x}{n}

Where:

\sum x is the sum of given observations

n is the number of observations

\sum x=87.12

n=50

\therefore Mean =\frac{87.12}{50}= 1.74 rounded to two decimal places

To find the median, we need to first arrange the data in ascending order but we are already given the data in ascending order.

Therefore, the median is:

Median=\left(\frac{n+1}{2} \right)^{th} item

                  =\left(\frac{51}{2} \right)^{th} item

                  =25.5^{th} item

                  =1.52+0.5(1.54-1.52)

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Therefore, the median = 1.53

4 0
3 years ago
Write and evaluate the expression. Then, complete the statements. A 1-column table with 5 rows. Column 1 is labeled Multiplicati
77julia77 [94]

Yuna ran three times as many kilometers so here expression should be 3k and the answer is 36.6

We have given that k = 12. 2

We have to find the expression

<h3>What is the writing and evaluating the expression?</h3>

Expressions are considered to be mathematical statements that have at least of two terms comprised of numbers or variables that should be linked. It could be of addition, subtraction, multiplication, or division.

Write the expression as  3k

Second, substitute 12.2 in for the variable, k.

Third,  simplify by  multiplying 3 and 12.2.

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Learn more about expression here:

brainly.com/question/723406

4 0
2 years ago
PLEASE HELP!!!!!!!!!!
Oksanka [162]

Answer:

B

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Data set A contains value 168, which does not show up on the plot.

The only remaining choice is B.

_____

In order, the data values of set B are ...

... 91, 114, 120, 126, 128, 128 134, 136, 139, 142, 152

The median value of these 11 is the 6th one: 128. The median values of the remaining two sets of 5 are 120 and 139, making these values the quartiles at the ends of the box. The value 91 is more than 1.5 times the IQR (19) below the 1st quartile, so is considered an outlier. (The cutoff is 120-1.5·19=91.5.)

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8a+8a+40
It is equivalent
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