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Varvara68 [4.7K]
2 years ago
15

What’s the molar mass for N2O5

Mathematics
2 answers:
RUDIKE [14]2 years ago
7 0
Dinitrogen Pentoxide
Molar mass-- 108.0104<span>
</span>
Nimfa-mama [501]2 years ago
4 0
The molar mass of N2O5 (Dinitrogen pentoxide) is 108.01 g/mol.
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Out of students appeared in an examination 75% passed in English, 55%. passed in Mathematics, 5% failed in both subjects and 21
rusak2 [61]

Based on the percentage that passed English and those who passed Mathematics and those who failed and passed both, the total number of students who appeared in the examination are 60 students.

The number of students who passed only in Math are 12 students.

<h3>What number of students sat in the exam?</h3>

This can be found as:

= Total who passed English only + Total who passed Math only + Total who failed both + Total who passed both

Assuming the total is n, the equation becomes:

n = 0.75n - 21 + 0.55n - 21 + 21 + 0.05n

n = 1.35n - 21

21 = 0.35n

n = 21 / 0.35

= 60 students

The number who passed mathematics only is:

= (60 x 55%) - students who passed both

= 33 - 21

= 12 students

Find out more on Venn diagrams at brainly.com/question/24581814

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4 0
1 year ago
Of the total amount of available water on the earth, what percent is usable?
prohojiy [21]
Only 20%of earths water is useable
8 0
3 years ago
Answer this question please and thank you
Fiesta28 [93]

Answer:

7/8 to the 7th power

Step-by-step explanation:

4 0
3 years ago
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Find the area of the regular 20​-gon with radius 77 mm.
butalik [34]
The area of a polygon equals
area = circumradius² * number of sides * sin (360 / # of sides) / 2
area = 77² * 20 * sin (360 / 20) / 2
area = 77² * 20 * sin (18) / 2
area = 118,580 * 0.30902 / 2
area = <span> <span> <span> 36,643.59 </span> </span> </span> / 2
area = 18,321.8 square millimeters


3 0
2 years ago
There are 100 students at a college who have taken a course in calculus, 110 who have taken a course in discrete mathematics, an
vesna_86 [32]

Answer:

110 students

Step-by-step explanation:

The number of students who have only taken calculus is given by the number of students who have taken calculus minus the students who have taken both classes:

C =100 -50\\C= 50\ students

The number of students who have only taken discrete mathematics given by the number of students who have taken discrete mathematics minus the students who have taken both classes:

D =110 -50\\C= 60\ students

The number of students that have taken a course in either calculus or discrete mathematics is:

E = C+D = 50+60\\E= 110\ students

7 0
2 years ago
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