So, f[x] = 1/4x^2 - 1/2Ln(x)
<span>thus f'[x] = 1/4*2x - 1/2*(1/x) = x/2 - 1/2x </span>
<span>thus f'[x]^2 = (x^2)/4 - 2*(x/2)*(1/2x) + 1/(4x^2) = (x^2)/4 - 1/2 + 1/(4x^2) </span>
<span>thus f'[x]^2 + 1 = (x^2)/4 + 1/2 + 1/(4x^2) = (x/2 + 1/2x)^2 </span>
<span>thus Sqrt[...] = (x/2 + 1/2x) </span>
It’s neither, and this is because the slope is not opposite or the same, the same y intercept yes...but there isn’t any parallel or perpendicular features...you can see this when you graph it :)
Hello :
f(x) = <span>a(x-k)²+k....... the point vertex is (h , k )
in this exercice : h = -3 and k = -1 s0 f(x) = a(x+3)²-1
find : a
but f(0)=8
a(0+3)² -1 = 8
9a-1=8
9a =9
a=1
f(x) =(x+3)²-1 =x²+6x+9-1
f(x) = x²+6x+8 .... (</span><span>the quadratic function in standard form )</span>
Answer: the price per charm
Step-by-step explanation:
not really sure but i think 60 is the price of the beacelet and since x is the charms 25 must be the price per charm because 25 is multiplyed with x.
does that make sense?
We know that
∠ TSR = 84°
if SQ bisects ∠ <span>TSR
then
</span>∠ RSQ = ∠ TSR/2
<span>so
</span>∠ RSQ = (1/2)*84°----- 42°
∠ RSQ = 3x-9
3x-9=42-------> 3x=42+9------> 3x=51-----> x=51/3-----> x=17°
<span>
the answer is
</span>x=17°<span>
</span>
