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Vlada [557]
4 years ago
8

Please help!!

Mathematics
1 answer:
solniwko [45]4 years ago
6 0
C I found this on apex and it helped me
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Write in ordinary form : 6 x 10^-4
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6x10^-4
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PLEASE PLEASE PLEASE PLEASE PLEASE HELP ME PLEASE HELP!?!?!!?!?!?!?!!?!!?!
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\text{Goal: Find } x \text{ such that:} \\ 2^x > 4x + 12

2^x > 4x + 12 \\ 2^x > 4(x + 3) \\ 2^{x - 2} > x + 3

\text{A lemma: } \\ \text{It is given that: } \\ 2^n > 2n + 1, \text{ } n > 3
\text{This can be proven by Mathematical Induction.}
\text{Using this lemma, we can manipulate the expression:} \\ 2^{x - 2} > 2(x - 2) + 1 = 2x - 3, \text{ } x > 5 \\ 2\cdot 2^{x - 2} > 2(2x - 3) \\ 2^{x - 1} > 4x - 12 \\ 2^{x - 1} + 24 > 4x + 12

\text{Observe the following: } 2^x \text{ will always grow faster than } 2^{x - 1} \\ \text{This implies that } 2^{x} > 2^{x - 1} + 24 > 4x + 12, \text{ given that } x > 5

\text{This means that the first month } f(x) > g(x) \text{ is Month 6.}
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3 years ago
Solve for y: y÷1 7/9 = 3/4
skelet666 [1.2K]

Answer:

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Step-by-step explanation:

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No

Step-by-step explanation:

Just because the derivative is 0 at a point doesn't necessarily mean it is a relative minimum or maximum.  You must be able to evaluate the derivative on both sides of the point to determine if it changes signs.  Since endpoints have only one side, they cannot be relative maximums or minimums.

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a student has reflected the patterns as given below are the reflections correct and what advice would yiu give them
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Step-by-step explanation:

We need the rest of the question please.

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