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11111nata11111 [884]
2 years ago
7

If carbon dioxide, methane, and water vapor were not in the atmosphere, then

Mathematics
1 answer:
Savatey [412]2 years ago
3 0
<h2>Answer:</h2>

D. The Earth's surface would be much colder than it is.

<h3>Step-by-step explanation:</h3>

This is because warm temperatures and high levels of atmospheric carbon dioxide happen at about the same time. So if atmospheric carbon dioxide concentrations double warm up by between 2 and 4.5 degrees Celsius. On the other hand, water vapor promotes, as the greatest contributor, to the Earth’s greenhouse effect. In this way, if carbon dioxide, methane, and water vapor were not in the atmosphere, then it's obvious that the Earth's surface would be much colder than it is.

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\bf f=k\sqrt{t}\quad \textit{we also know that }&#10;\begin{cases}&#10;f=300\\&#10;t=8&#10;\end{cases}\implies 300=k\sqrt{8}&#10;\\\\\\&#10;\cfrac{300}{\sqrt{8}}=k\implies \cfrac{300}{\sqrt{2^2\cdot 2}}=k\implies \cfrac{300}{2\sqrt{2}}=k\implies \cfrac{150}{\sqrt{2}}=k&#10;\\\\\\&#10;\textit{and we can \underline{rationalize} it to }\cfrac{150\sqrt{2}}{2}\implies 75\sqrt{2}=k

\bf thus\qquad f=\stackrel{k}{75\sqrt{2}}\sqrt{t}\implies \boxed{f=75\sqrt{2t}}\\\\&#10;-------------------------------\\\\&#10;\textit{now, when t = 72, what is \underline{f}?}\qquad f=75\sqrt{2(72)}
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5 0
2 years ago
a cardboard box holds 31.25 cubic inches of creamy butter. The butter is molded into a square prism that is 5 inches long. How m
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Answer:

62.5 \:in^2

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Length of the Molded Square Prism =5 Inches

Let the length of the square cross sectional area = x

Volume of the Prism=x^2l

Since l=5 Inches

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Next, we determine the surface area of the New Cardboard box to be made.

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Total Surface Area=2(x^2+xl+xl)=2(x^2+2xl)

=2(2.5^2+2(2.5)(5))\\=2(6.25+25)\\=2*31.25\\=62.5 \:in^2

Therefore, 62.5 \:in^2 of cardboard is needed,

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