Porobability distribution of X
x P(x)
0 0.2
1 0.4
2 0.4
Total .1.0
i] Expectation
Mean=Σxp
Variance=x²p-(∑xp)²
thus:
Mean=(0*0.2)+(1*0.4)+(2*0.4)
=0+0.4+0.8
=1.2
ii] Variance
Variance=[(0²*0.2)+(1²*0.4)+(2²*0.4)]-(1.2)²
=[0+0.4+1.6]-1.44
=0.56
hence:
standard deviation=sqrt(0.56)=0.74833
Answer:3 if 6 divided by 2 because 2 times 3 is 6
Step-by-step explanation:2 times 3 I guess really trig in my opinion im only in middle school
The value of du becomes 4 by integration.
According to the statement
we have given a two statement which are u - 4x and u = x + 1.
And we have to find the value of du by the use of integration.
An Integral assigns numbers to functions in a way that describes the data.
So,
From u - 4x
here du becomes by derivative
du - 4dx/du
du = 4dx/du. -(1)
And in u = x + 1.
here du becomes
du = dx/du -(2)
by comparing both terms from equation (1) and (2) we get the value of du
du = 4.
the value of du is 4.
So, The value of du becomes 4 by integration.
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<h3>
Answer: Choice A) 148 degrees</h3>
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Explanation:
Let point A be the center of the circle.
Arc DCF is 316 degrees. Arc FG is 20 degrees. Subtracting the arc measures gives 316-20 = 296 which is the measure of arc DCG, and by extension, it is the measure of reflex angle DAG. The acute angle DAG is 360-296 = 64 degrees
Triangle DAG is isosceles with AD = AG, so the base angles are ADG and AGD. Let's call each of these angles x for now. The sum of the three angles add to 180
x+x+64 = 180
2x+64 = 180
2x = 180-64
2x = 116
x = 116/2
x = 58
Therefore angle ADG is 58 degrees. It adds to angle ADB = 90 to get 90+58 = 148, which is the measure of angle BDG.
Note: angle ADB is 90 because tangent BD forms a right angle with the radius AD.
Another note: angle ADG is half that of the arc it cuts off, so in a sense it's similar to an inscribed angle
60% of 120 is 72. Therefore, Mark has only saved 72 dollars.