Answer:
See below
Step-by-step explanation:
REMEMBER sec = 1/cos ...so the left side is
[1/cos -1] / [1/cos +1 ]
get common denominator for numerator and denominator
[ (1 -cos) /cos ] / [ (1+cos) / cos ]
now flip the bottom fraction and multiply to get
[(1-cos/cos) ] * [ cos / (1+cos) ] which simplifies to ( the 'cos' term cancels)
(1-cos) / (1+cos) done !
Answer:
We know that the area of the square of side length L is:
A = L*L = L^2
In this case, we know that the area is:
A = 128*x^3*y^4 cm^2
Then we have:
L^2 = 128*x^3*y^4 cm^2
If we apply the square root to both sides we get:
√(L^2) = √( 128*x^3*y^4 cm^2)
L = √(128)*(√x^3)*(√y^4) cm
Here we can replace:
(√x^3) = x^(3/2)
(√y^4) = y^(4/2) = y^2
Replacing these two, we get:
L = √(128)*x^(3/2)*y^2 cm
This is the simplest form of L.
In a conventional gradient, the amount of money in period one is known as the base amount.
<h3>What is an arithmetic gradient? </h3>
An arithmetic gradient series is a cash flow series that either increases or decreases by a constant amount each period.
<h3>What is a base amount?</h3>
Base amount is the fundamental numerical assumption from which something is begun or estimated in a given arithmetic series. It usually occurs in period for a conventional gradient.
Thus, in a conventional gradient, the amount of money in period one is known as the base amount.
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The value of f(5) is 49.1
Step-by-step explanation:
To find f(x) from f'(x) use the integration
f(x) = ∫ f'(x)
1. Find The integration of f'(x) with the constant term
2. Substitute x by 1 and f(x) by π to find the constant term
3. Write the differential function f(x) and substitute x by 5 to find f(5)
∵ f'(x) = 
+ 6
- Change the root to fraction power
∵ = 
∴ f'(x) = + 6
∴ f(x) = ∫ + 6
- In integration add the power by 1 and divide the coefficient by the
new power and insert x with the constant term
∴ f(x) = 
+ 6x + c
- c is the constant of integration
∵ 
∴ f(x) = 
+ 6x + c
- To find c substitute x by 1 and f(x) by π
∴ π = 
+ 6(1) + c
∴ π = + 6 + c
∴ π = 6.4 + c
- Subtract 6.4 from both sides
∴ c = - 3.2584
∴ f(x) = + 6x - 3.2584
To find f(5) Substitute x by 5
∵ x = 5
∴ f(5) = 
+ 6(5) - 3.2584
∴ f(5) = 49.1
The value of f(5) is 49.1
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Slope = (y2 - y1) / (x2 - x1)
(0,4)...x1 = 0 and y1 = 4
(-8,-1)...x2 = -8 and y2 = -1
now we sub and solve
slope = (-1 - 4) / (-8 - 0) = -5/-8 = 5/8 <=
