Ask question

Ask question

All categories

3 years ago

5

Helppppppppppppppppppppppppppppppppppppppppppppppppppppppp

2 answers:

victus00 [196]3 years ago

7 0

Answer:

s=24

Step-by-step explanation:becuase this is an improper fracton

so you do 8x the 3 that is shown above the you will have you r answer plz mark as brainliest thx

ANTONII [103]3 years ago

5 0

Answer:

s=24

Step-by-step explanation:

You might be interested in

This is due like right now, please help me!!!!

Varvara68 [4.7K]

$\bold{\huge{\orange{\underline{ Solution }}}}$

$\bold{\underline{ Given \: Rules}}$

<u>The </u><u>sum</u><u> </u><u>of </u><u>the </u><u>number </u><u>in </u><u>each </u><u>of </u><u>the </u><u>four </u><u>rows </u><u>is </u><u>the </u><u>same </u>
<u>The </u><u>sum </u><u>of </u><u>the </u><u>numbers </u><u>in </u><u>each </u><u>of </u><u>the </u><u>three </u><u>columns </u><u>is </u><u>the </u><u>same</u>
<u>The </u><u>sum </u><u>of </u><u>any </u><u>row </u><u>does </u><u>not </u><u>equal </u><u>the </u><u>sum </u><u>of </u><u>any </u><u>column </u>

$\bold{\underline{ Let's \: Begin}}$

<u>According </u><u>to </u><u>the </u><u>Second</u><u> </u><u>rule </u><u>:</u><u>-</u>

$\sf{ 75+b+83=76+80+d=a+81+85+78+c+e }$

$\sf{ 158 + b = 156 + d = 166 + a = 78 + c + e ...(1)}$

<u>According </u><u>to </u><u>the </u><u>first </u><u>rule </u><u>:</u><u>-</u><u> </u>

$\sf{ 75+76+a+78 = b+80+81+c = 83+86+d+e}$

$\sf{ 229 + a = 161 + b + c = 168 + d + e ...(2)}$

<u>From </u><u>(</u><u> </u><u>1</u><u> </u><u>)</u><u> </u><u>we </u><u>got </u><u>:</u><u>-</u>

$\sf{ 158 + b = 166 + a, 156 + d = 166 + a }$

$\sf{ b = 166 - 158 + a, d = 166 - 156 + a }$

$\sf{ b = 8 + a, d = 10 + a ...(3)}$

<u>Subsitute </u><u>(</u><u>3</u><u>)</u><u> </u><u>in </u><u>(</u><u> </u><u>2</u><u> </u><u>)</u><u> </u><u>:</u><u>-</u>

$\sf{229+a = 161+8+a+c = 168+10+a+e}$

$\sf{ 229+a = 169+a+c = 178+a+e}$

<u>We</u><u> </u><u>can </u><u>write </u><u>it </u><u>as </u><u>:</u><u>-</u>

$\sf{ 229+a = 169+a+c \:or\:229+a = 178+a+e}$

$\sf{ c = 299-169+a-a\:or\:e = 229-178+a-a}$

$\sf{ c = 60 \: and \: e = 51 }$

<u>Subsitute </u><u>the </u><u>value </u><u>of </u><u>c </u><u>and </u><u>e </u><u>in </u><u>(</u><u> </u><u>1</u><u> </u><u>)</u><u>:</u><u>-</u>

$\sf{ 158 + b = 156 + d = 166 + a = 78 + 60 + 51 }$

$\sf{ 158 + b = 156 + d = 166 + a = 189}$

<u>Now</u><u>, </u>

$\sf{ For \: b, 158 + b = 189 }$

$\sf{ b = 189 - 158 }$

$\sf{ b = 31}$

$\sf{ For \: d , 156 + b = 189 }$

$\sf{ d = 189 - 156 }$

$\sf{ d = 33}$

$\sf{ For \: a, 166 + a = 189 }$

$\sf{ a = 189 - 166 }$

$\sf{ a = 23 }$

Hence, The value of a, b, c, d and e is 23, 31 ,60 ,33 and 51 .

8 0

3 years ago

Two number cubes are tossed. What is P(4, 6)?<br><br> O.1/6<br> O.1/12<br> O.1/3<br> O.1/36

Bezzdna [24]

The value of P(4, 6) when the two number cubes are tossed is 1/36

<h3>How to determine the probability?</h3>

On each number cube, we have:

Sample space = {1, 2, 3, 4, 5, 6}

The individual probabilities are then represented as:

P(4) =1/6

P(6) =1/6

The value of P(4, 6) when the two number cubes are tossed is:

P(4, 6) = P(4) * P(6)

This gives

P(4, 6) = 1/6 * 1/6

Evaluate

P(4, 6) = 1/36

Hence, the value of P(4, 6) when the two number cubes are tossed is 1/36

Read more about probability at:

brainly.com/question/24756209

#SPJ1

6 0

1 year ago

Cuánto es –a +28=14???

eimsori [14]

Answer:

a=14

Step-by-step explanation:

-a+28=14

So -a=-14

so a=14

6 0

2 years ago

Read 2 more answers

Teresa says that because the diagonals of a parallelogram bisect each other, if one diagonal is 4.2 cm, the other diagonal must

saw5 [17]

Answer:

See it in the pic.

Step-by-step explanation:

See it in the pic.

3 0

3 years ago

RT and GJ are chords that intersect at point H.

Lubov Fominskaja [6]

Answer:

20

Step-by-step explanation:

4 0

4 years ago

Read 2 more answers