Question:
Solve the equation 2x2−5x+3=0 by the method of completing square.
Answer:
We have,
2x2−5x+3=0
⇒x2−25x+23=0 (Dividing throughough by 2)
⇒x2−25x=−23 (Shifting the constant term on RHS)
⇒x2−2(45)x+(45)2=(45)2−23 (Adding (21Coeff.ofx)2 onboth sides)
⇒(x−45)2=1625−23⇒(x−45)2=16
Answer:
y = -3x + 4
Step-by-step explanation:
Slope intercept form : y = mx +b
6x + 2y = 8
2y = -6x + 8
Divide the entire equation by 2

y = -3x + 4
(x+9)(x+8) = x^2 +17x + 72
(x- 7)(x+8) = x^2 + x - 72
(x- 5)(x- 6) = x^2 -11x + 30
(2x + 3)(3x+2) = 6x^2 + 13x +6
(5x - 4)(2x-5) = 10x^2 - 33x + 20
(x-4)^2 = x^2 -8x + 16
(2x+1)^2 = 4x^2 +4x + 1
(4x+3)(4x-3) = 16x^2 - 9
the answer is A i believe
Perform the operation in the choices to determine the coefficients of the terms.
(Addition) -4x - 1 + 2x + 4 = -2x + 3
(Subtraction) -4x - 1 - (2x + 4) = -6x - 5
(Multiplication) (-4x - 1)(2x + 4) = -8x² -18x -4
Thus, the answer is multiplication as it gives a numerical coefficient equal to -18.