John's. Find the first common multiple of both denominators, in this case it's going to be ten, then the number you had to multiply to change these numbers to the common multiply you do to the numerators. so it works out like so:
Deena has a bottle of 4/10
John has a bottle of 25/10 or 2 1/2 (simplified)
Answer:
0.0025 = 0.25% probability that both are defective
Step-by-step explanation:
For each item, there are only two possible outcomes. Either they are defective, or they are not. Items are independent of each other. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which
is the number of different combinations of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.
5 percent of these are defective.
This means that 
If two items are randomly selected as they come off the production line, what is the probability that both are defective
This is P(X = 2) when n = 2. So


0.0025 = 0.25% probability that both are defective
Hey there!
The answer to your question is 
Given:

First, we distribute the negative sign to both terms (
) This would make the
negative and the
positive, so we have:

Add them together and we get:

Have a nice day!
5.C
6.A
Hope this helps and is correct
Answer:
Step-by-step explanation:
Hello, when you have an equation like y = ax+b you know that this is a line.
In this example, the function is defined in two different intervals.
For x < 1 this is the line y = 4 + x
and for x>=1 this is the line y = 4 - 2x
At the frontier, x= 1, we have 4+1=5 on one side and 4-2=2 on the other side, we we expect a "jump" in the graph.
Except that "jump"you just have to draw lines, so if you have two points you can draw them right.
For x<1, the line is passing by (-4,0) and (0,4)
And you have to stop for x<1 so the point (1,5) is not on the graph.
for x>=1 the points (1,2) and (2,0) are on the graph and we just have to draw the line.
I attached the graph.
Thanks