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2 years ago

A student expanded an expression, as shown. Is the student's work correct? Explain why or why not.

Mathematics

2 answers:

Schach [20]2 years ago

7 0

Answer:

No, the work is not correct. The distributive property was not used properly to expand the expression. Negative 6 should be multiplied by both terms in the parentheses. The second product should be -6 times -2/13 to get positive 12/13.

Step-by-step explanation:

Just answered the question. Just copy and paste its the work to work answer

Ugo [173]2 years ago

4 0

Answer:

No.

Step-by-step explanation:

Honestly, I'm not entirely certain. The steps are formatted very weirdly and I'm not sure what they are.

I believe the first step is -6(4x-213) which is a different expression than the last step which is (-24x-1213) but those aren't very similar.

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<h3>What is the hang time equation?</h3>

The hang-time of the ball for a player of jump h is given by:

$t = 2\left(\frac{2h}{32}\right)^{\frac{1}{2}}$

The expression can be simplified as:

$t = 2\sqrt{\frac{h}{16}}$

For a player that has a hang time of 0.9s, the jump is found as follows:

$0.9 = 2\sqrt{\frac{h}{16}}$

$\sqrt{\frac{h}{16}} = \frac{0.9}{2}$

$(\sqrt{\frac{h}{16}})^2 = \left(\frac{0.9}{2}\right)^2$

$h = 16\left(\frac{0.9}{2}\right)^2$

h = 3.24 feet.

For a player that has a hang time of 0.8s, the jump is found as follows:

$0.8 = 2\sqrt{\frac{h}{16}}$

$\sqrt{\frac{h}{16}} = \frac{0.8}{2}$

$(\sqrt{\frac{h}{16}})^2 = \left(\frac{0.8}{2}\right)^2$

$h = 16\left(\frac{0.8}{2}\right)^2$

h = 2.56 feet.

The difference is given by:

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More can be learned about equations at brainly.com/question/25537936

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