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Pavlova-9 [17]
3 years ago
13

A student expanded an expression, as shown. Is the student's work correct? Explain why or why not.

Mathematics
2 answers:
Schach [20]3 years ago
7 0

Answer:

No, the work is not correct. The distributive property was not used properly to expand the expression. Negative 6 should be multiplied by both terms in the parentheses. The second product should be -6 times -2/13 to get positive 12/13.

Step-by-step explanation:

Just answered the question. Just copy and paste its the work to work answer

Ugo [173]3 years ago
4 0

Answer:

No.

Step-by-step explanation:

Honestly, I'm not entirely certain. The steps are formatted very weirdly and I'm not sure what they are.

I believe the first step is -6(4x-213) which is a different expression than the last  step which is (-24x-1213) but those aren't very similar.

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The coordinates of an ordered pair have opposite signs. In which quadrant(s) must the ordered pair lie?
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3 years ago
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6. What is the y-value to the solution of<br> y = 5x -4<br> y = 2x + 8?
Angelina_Jolie [31]

Answer:

y = 16, don't know if I'm 100% right but hope this helps.

Step-by-step explanation:

since they both equal Y they may be equal to each other

Then you would subtract 2x from both sides canceling it out on one side

2x + 8 = 5x - 4

-2x         -2x

This would make the equation 8 = 3x - 4

next you add the 4 from both sides

8  = 3x - 4

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This will leave you with 12 = 3x

now you divide 3 from both sides and 12/3 = 4 makes X = 4

next you take (4) and plug it in to one of the equations

y = 2(4) + 8

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y = 16

8 0
3 years ago
what are the solution(s) to the quadratic equation 9x2 = 4? x = 4/9 and x = -4/9 x = 4/9 and x = -2/3 x = 3/2 and x = -3/2 no re
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6 0
4 years ago
Your friend heard that functions are studied in intermediate and college algebra courses. He asks you what a function is. Provid
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A function is defined as the relationship between variables in which the alteration of one variable affects the other variable.

Suppose we are having a function:-

F(x)=2x^2-1

In the above function f(x) is an independent variable and the 2x^2-1 is a dependent variable so for the different values of x the value of the dependent function varies.

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3 0
3 years ago
Mr. Wilson invested money in two accounts his total investment was $8000. If one account pays 6% and interest and the other pays
Anuta_ua [19.1K]

Answer:

<u>Mr. Wilson invested $ 2,000 in the 12% simple interest account and $ 6,000 in the 6% simple interest account.</u>

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Amount of the investment = $ 8,000  

Interest rate of the first account= 6% simple  

Interest rate of the second account= 12% simple  

Interest of the accounts in a year = $ 600  

2. How much did he invest in each account?

For answering the question, we will use the following equation:  

x = Amount invested in the first account  

8,000 - x = Amount invested in the second account  

0.06x + 0.12 * (8,000 - x) = 600

0.06x + 960 - 0.12x = 600

-0.06x = 600 - 960 (Subtracting 960 at both sides)

-0.06x = -360

x = -360/-0.06

x = 6,000 ⇒ 8,000 - x = 2,000  

<u>Mr. Wilson invested $ 2,000 in the 12% simple interest account and $ 6,000 in the 6% simple interest account.</u>

6 0
3 years ago
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