The answer is 30 60 and 90 because those are the only 3 numbers that are divisible by both 3 and 10 and are two digits.
Answer:
see explanation
Step-by-step explanation:
Choose any value for x, substitute into the equation and solve for y, that is
x = - 1
2(- 1) + y = 8
- 2 + y = 8 ( add 2 to both sides )
y = 10
---------
x = 0
2(0) + y = 8
0 + y = 8
y = 8
----------------
x = 1
2(1) + y = 8
2 + y = 8 ( subtract 2 from both sides )
y = 6
---------------
x = 3
2(3) + y = 8
6 + y = 8 ( subtract 6 from both sides )
y = 2
----------------
4 possible solutions are (- 1, 10 ), (0, 8 ), (1, 6 ) and (3, 2 )
Answer:
x^2 - 2x - 8.
Step-by-step explanation:
Using long division:
x - 2)x^3 - 4x^2 - 4x + 16( x^2 - 2x - 8 <------ Quotient
x^3 - 2x^2
-2x^2 - 4x
-2x^2 + 4x
- 8x + 16
-8x + 16
............
Answer:
48.06
Step-by-step explanation:
b^2+c^2=A^2
45+16=42.06
add the extra 6
The question is asking how many combinations of two people can be made from a group of ten people.
Using the formula C(10,2) = 10!/(2! x (10 - 2)! = 10!/(2! x 8!) = 45 handshakes.
A simple way to prove this is each person shakes the hand of 9 other people
10 x 9 = 90 but this counts every handshake from the view of both people involved.
The actual number of handshakes is therefore 90 / 2 = 45
