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3 years ago

How many times larger is 9 × 10^7 than 3 × 10^6? A. 30 B. 0.3 C. 300 D. 3

Mathematics

2 answers:

jekas [21]3 years ago

8 0

Answer:

A. 30.

Step-by-step explanation:

9 x 10^7 = 90,000,000

3 * 10^6 = 3,000,000

Dividing we get 90/3

= 30.

horrorfan [7]3 years ago

3 0

Answer:

A.30

Step-by-step explanation:

9 × 10^7 = 90 000 000

3 × 10^6 = 3 000 000

90 000 000 / 3 000 000 = 30

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A class of 24 students went on a picnic. They had a choice between having a turkey sandwich or a vegetarian sandwich. Eighteen s

Alekssandra [29.7K]

I believe it is the ratio 3 : 1.

18 students chose the turkey sandwich.

Since the class has a total of 24 students, we can deduce that 6 students chose the vegetarian sandwich.

This gives us a ratio of 18 : 6.

When simplified, we get a ratio of 3 : 1.

5 0

3 years ago

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ki77a [65]

Answer:

B i think

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

PLEASE ANSWER -( 1 - 6n )

Slav-nsk [51]

Answer:

6n-1

Step-by-step explanation:

Re-arrange
-(1 - 6n)
-(-6n + 1)

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4 0

2 years ago

A lamina with constant density rho(x, y) = rho occupies the given region. Find the moments of inertia Ix and Iy and the radii of

jenyasd209 [6]

Answer:

Ix = Iy = $\frac{ρπR^{4} }{16}$

Radius of gyration x = y = $\frac{R}{4}$

Step-by-step explanation:

Given: A lamina with constant density ρ(x, y) = ρ occupies the given region x2 + y2 ≤ a2 in the first quadrant.

Mass of disk = ρπR2

Moment of inertia about its perpendicular axis is $\frac{MR^{2} }{2}$ . Moment of inertia of quarter disk about its perpendicular is $\frac{MR^{2} }{8}$ .

Now using perpendicular axis theorem, Ix = Iy = $\frac{MR^{2} }{16}$ = $\frac{ρπR^{4} }{16}$ .

For Radius of gyration K, equate MK2 = MR2/16, K= R/4.

3 0

3 years ago

Are the equations 3x - -9 and 4x - -12 equivalent? Explain. Please Help!!

konstantin123 [22]

No because when you do 3*--9 = 27 and 4*--12 =48

7 0

2 years ago