311(1.50)+.50x=385.50
would be your equation
Answer:
A 9x--12 i hope this helps
Hi!
To compare this two sets of data, you need to use a t-student test:
You have the following data:
-Monday n1=16; <span>x̄1=59,4 mph; s1=3,7 mph
-Wednesday n2=20; </span>x̄2=56,3 mph; s2=4,4 mph
You need to calculate the statistical t, and compare it with the value from tables. If the value you obtained is bigger than the tabulated one, there is a statistically significant difference between the two samples.

To calculate the degrees of freedom you need to use the following equation:

≈34
The tabulated value at 0,05 level (using two-tails, as the distribution is normal) is 2,03. https://www.danielsoper.com/statcalc/calculator.aspx?id=10
So, as the calculated value is higher than the critical tabulated one,
we can conclude that the average speed for all vehicles was higher on Monday than on Wednesday.
$250 c+ $ 180 g > $ 950
<u>Step-by-step explanation:</u>
As a cryptographer (c), Miyoko earns per day = $ 250
As a geologist (g) , Miyoko earns per day = $ 180
So the equation comes to be $250 c+ $ 180 g = $ 950
The equation can be rewritten to find c as, (950-180 g) / 250
The equation can be rewritten to find g as, (950 - 250 c) / 180
Plugin different values of c and g in the above 2 equations, we can find that ,
To achieve the goal, Miyoko requires to be a geologist for 3 days and crpytographist for 2 days.
Answer:
hope this helps you. look it once