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ZanzabumX [31]
2 years ago
12

Past the core

Mathematics
1 answer:
Basile [38]2 years ago
5 0

Answer:

Building's shadow length = 180 feet.

Step-by-step explanation:

Given:

A 50-foot flagpole is at the entrance of a building that is 300 feet tall.

Its forms a right angled triangle from both ends,both of them are similar because the angle of the sun is the same at the same time of day.

From similar triangle property we can say that.

⇒ length of the building shadow times height of the flagpole's = length of the flagpole's shadow times height of the building

Or

\frac{length\ of\ the\ building\ shadow}{height\ of\ the\ building} =\frac{length\of\ the\ flagpole's\ shadow}{height\ of\ the\ flagpole's}

Plugging the values in the above equation we have,

Let length of the building shadow ='x' feet

⇒ \frac{x}{300} =\frac{30}{50}

⇒ \frac{x}{300}\times 300 =\frac{30}{50}\times 300

⇒ x=\frac{300\times 30}{50}

⇒ x=\frac{9000}{50}

⇒ x=180 feet.

So the length of the building shadow is 180 feet.

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quester [9]
Hi! 

To compare this two sets of data, you need to use a t-student test:

You have the following data:

-Monday n1=16; <span>x̄1=59,4 mph; s1=3,7 mph

-Wednesday n2=20;  </span>x̄2=56,3 mph; s2=4,4 mph

You need to calculate the statistical t, and compare it with the value from tables. If the value you obtained is bigger than the tabulated one, there is a statistically significant difference between the two samples.

t= \frac{X1-X2}{ \sqrt{ \frac{(n1-1)* s1^{2}+(n2-1)* s2^{2} }{n1+n2-2}} * \sqrt{ \frac{1}{n1}+ \frac{1}{n2}} } =2,2510

To calculate the degrees of freedom you need to use the following equation:

df= \frac{ (\frac{ s1^{2}}{n1} + \frac{ s2^{2}}{n2})^{2}}{ \frac{(s1^{2}/n1)^{2}}{n1-1}+ \frac{(s2^{2}/n2)^{2}}{n2-1}}=33,89≈34

The tabulated value at 0,05 level (using two-tails, as the distribution is normal) is 2,03. https://www.danielsoper.com/statcalc/calculator.aspx?id=10

So, as the calculated value is higher than the critical tabulated one, we can conclude that the average speed for all vehicles was higher on Monday than on Wednesday.



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<u>Step-by-step explanation:</u>

As a cryptographer (c), Miyoko earns per day = $ 250

As a geologist (g) , Miyoko earns per day = $ 180

So the equation comes to be $250 c+ $ 180 g = $ 950

The equation can be rewritten to find c as, (950-180 g) / 250

The equation can be rewritten to find g as, (950 - 250 c) / 180

Plugin different values of c and g in the above 2 equations, we can find that ,

To achieve the goal, Miyoko requires to be a geologist for 3 days and crpytographist for 2 days.

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kykrilka [37]

Answer:

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