'll use the binomial approach. We need to calculate the probabilities that 9, 10 or 11
<span>people have brown eyes. The probability that any one person has brown eyes is 0.8, </span>
<span>so the probability that they don't is 1 - 0.8 = 0.2. So the appropriate binomial terms are </span>
<span>(11 C 9)(0.8)^9*(0.2)^2 + (11 C 10)(0.8)^10*(0.2)^1 + (11 C 11)(0.8)^11*(0.2)^0 = </span>
<span>0.2953 + 0.2362 + 0.0859 = 0.6174, or about 61.7 %. Since this is over 50%, it </span>
<span>is more likely than not that 9 of 11 randomly chosen people have brown eyes, at </span>
<span>least in this region. </span>
<span>Note that (n C r) = n!/((n-r)!*r!). So (11 C 9) = 55, (11 C 10) = 11 and (11 C 0) = 1.</span>
The results of the survey will most likely suffer from wording bias.
<h3><u>Wording Bias</u></h3>
The question asked in the survey contains certain characteristics that induce the respondent to think about the question asked in a negative way.
Thus, the word "wasteful" induces respondents to answer the question bearing in mind the negative criticism made by the questioner, which may influence the final answer.
Learn more about bias in brainly.com/question/1337465
28 tries. The ratio is 5:7, so once you multiply 5 by 4 to get 20, you do the same to 7 to get 28.
X² - 21x + 110
first you break it up into two parenthesis & since x is squared you need two x's
since 110 is positive and 21 is negitive, both of your signs need to be negitive
(x - ?)(x - ?)
then you need to think! what are the factors of 110?
Which of these factors add up to 21? those factors go in the parenthesis
Does this Help? Let me know if you need anything!
