Mi hermano ha ganado un dinero <em>devengado</em> de 8835 pesos en 15 días.
En esta pregunta debemos determinar el dinero <em>devengado</em> por un período de 15 días a partir de una tasa diaria <em>constante</em>. Esa cantidad es igual al producto de la tasa diaria <em>constante</em>, en pesos por día, y el número de días <em>trabajados</em>, en días:


Mi hermano ha ganado un dinero <em>devengado</em> de 8835 pesos en 15 días.
Para aprender más sobre álgebra y aritmética, invitamos cordialmente a ver esta pregunta: brainly.com/question/953809
Answer:
5 meters
Step-by-step explanation:
Based on the situation, it forms into a right triangle. So we will apply the Pythagorean Theorem here. The ladder acts as the hypotenuse while the height from the ground to the window serves as our side "a". We are tasked to solve for "b". Side "b" is the distance from foot of side a to the tip of side c which is the hypotenuse (ladder). We will derive the formula below to solve for b.
c = √( a² + b² )
c² = a² + b²
b² = c² - a²
b = √ ( c² - a² )
b = √ ( 13² - 12² )
b = 5 meters
Correct me if I'm wrong. I hope it helps.
X=6+3y
Let me know if you need the steps:)
Answer:
Her opportunity cost of reading 10 pages of sociology is 15 pages of Economics
Her opportunity cost of reading 18 pages of economics is 12 pages of sociology.
Step-by-step explanation:
For economics, Latasha reads 1 page in 2 mins (gotten by dividing the number of pages by the time taken to read it i.e 30 pages in 1 hr or 60 mins)
Her sociology is read 1 page in 3 mins (20 pages read in 60 mins)
To read 10 pages of sociology will take 30 mins. She will read 15 pages of Economics in the same time which is the opportunity cost.
In the same vein, It will take her 36 mins to read 18 pages of Economics at the same rate. This is the opportunity cost of reading 12 pages of Sociology (which she reads at 1 page in 3 mins).
Given a right angle triangle
The length of the legs are 4 and 7
we will find the hypotenuse using the Pythagorean theorem
So,
![\begin{gathered} h^2=7^2+4^2=49+16=65 \\ h=\sqrt[]{65}\approx8.062 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20h%5E2%3D7%5E2%2B4%5E2%3D49%2B16%3D65%20%5C%5C%20h%3D%5Csqrt%5B%5D%7B65%7D%5Capprox8.062%20%5Cend%7Bgathered%7D)
Rounding to the nearest tenth
So, the answer is the length of the third side = 8.1