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Gekata [30.6K]
3 years ago
9

Find the range of the data set: 7, 12, 15, 4, 23, 15, 25, 9

Mathematics
1 answer:
iVinArrow [24]3 years ago
4 0

Answer: Range = 21

Step-by-step explanation: you subtract the highest number by the lowest number in the set to find your range

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A rocket is launched from the Space Coast of Florida and can be seen from local schools. The angle of elevation from Western Hig
german

Answer:

365.73 miles

Step-by-step explanation:

Given that :

Angle of elevation (western high) = 41.25°

Angle of elevation (pine high) = 23.125

From the diagram attached :

Angle A = 180 - (41.25 + 13.125) = 115.625

Using the Sine rule :

a / SinA = b/SinB = c/sin C

512 / sin 115.625 = b / sin 41.25

554.68738 = b / sin 41.25

554.68738 * sin 41. 25 = b

b = 365.73 miles

8 0
3 years ago
What happens when you reflect a shape over the x-axis and then the y-axis. What is the one transformation that could have been p
Anna35 [415]

Answer:

Rotate 180 degrees with the center the origin (0,0)

Step-by-step explanation:

Try drawing a small square in the first quadrant, then reflect it like the direction. If you use tracing paper and and copy the figure, you will see that if you rotate the figure at the origin, it will land on the same spot as the translations.

8 0
1 year ago
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8 0
3 years ago
Y+3y-2=3, the linear equation will be correct but, if the answer what is the 3/4 70 of the number, perimeter, and value of x? wo
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4 0
2 years ago
Weights of cars passing over a bridge part 2<br>​
DaniilM [7]

Step-by-step explanation:

The solution to this problem is very much similar to your previous ones, already answered by Sqdancefan.

Given:

mean,  mu = 3550 lbs (hope I read the first five correctly, and it's not a six)

standard deviation, sigma = 870 lbs

weights are normally distributed, and assume large samples.

Probability to be estimated between W1=2800 and W2=4500 lbs.

Solution:

We calculate Z-scores for each of the limits in order to estimate probabilities from tables.

For W1 (lower limit),

Z1=(W1-mu)/sigma = (2800 - 3550)/870 = -.862069

From tables, P(Z<Z1) = 0.194325

For W2 (upper limit):

Z2=(W2-mu)/sigma = (4500-3550)/879 = 1.091954

From tables, P(Z<Z2) = 0.862573

Therefore probability that weight is between W1 and W2 is

P( W1 < W < W2 )

= P(Z1 < Z < Z2)

= P(Z<Z2) - P(Z<Z1)

= 0.862573 - 0.194325

= 0.668248

= 0.67 (to the hundredth)

6 0
3 years ago
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