Pizza palace charges $x

balu736 [363]

Where’s the photo? But I need to answer with a photo 3.8 ft and 1.1 ft equals 4.9 ft

7 0

3 years ago

ILL GIVE THE BRAINLIEST pls help me with this question EVERYTHING IS IN THE PICTURE PLS HELP DUE TODAY IF YOU PUT A WRONG ANSW

balu736 [363]

Answer:

60 yd

Step-by-step explanation:

Volume is length x width x height. Therefore in this case, we do 4x3x5 which turns out to be 60. Also don't forget to add yd after your answer because this is measured in yards.

8 0

3 years ago

Read 2 more answers

Lightbulbs of a certain type are advertised as having an average lifetime of 750 hours. The price of these bulbs is very favorab

Katyanochek1 [597]

Answer:

(a) Customer will not purchase the light bulbs at significance level of 0.05

(b) Customer will purchase the light bulbs at significance level of 0.01 .

Step-by-step explanation:

We are given that Light bulbs of a certain type are advertised as having an average lifetime of 750 hours. A random sample of 50 bulbs was selected, and the following information obtained:

Average lifetime = 738.44 hours and a standard deviation of lifetimes = 38.2 hours.

Let Null hypothesis, $H_0$ : $\mu$ = 750 {means that the true average lifetime is same as what is advertised}

Alternate Hypothesis, $H_1$ : $\mu$ < 750 {means that the true average lifetime is smaller than what is advertised}

Now, the test statistics is given by;

T.S. = $\frac{Xbar-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, X bar = sample mean = 738.44 hours

s = sample standard deviation = 38.2 hours

n = sample size = 50

So, test statistics = $\frac{738.44-750}{\frac{38.2}{\sqrt{50} } }$ ~ $t_4_9$

= -2.14

(a) Now, at 5% significance level, t table gives critical value of -1.6768 at 49 degree of freedom. Since our test statistics is less than the critical value of t, so which means our test statistics will lie in the rejection region and we have sufficient evidence to reject null hypothesis.

Therefore, we conclude that the true average lifetime is smaller than what is advertised and so consumer will not purchase the light bulbs.

(b) Now, at 1% significance level, t table gives critical value of -2.405 at 49 degree of freedom. Since our test statistics is higher than the critical value of t, so which means our test statistics will not lie in the rejection region and we have insufficient evidence to reject null hypothesis.

Therefore, we conclude that the true average lifetime is same as what it has been advertised and so consumer will purchase the light bulbs.

6 0

3 years ago

Two fair dice are rolled 3 times and the sum of the numbers that come up is recorded. Find the probability of these events. a. T

alexandr402 [8]

Answer:

Step-by-step explanation:

Given that two fair dice are rolled 3 times and the sum of the numbers that come up is recorded.

a) The sum is 4 on each of the three rolls.

(1,3) (2,2) (3,1) HEnce for one throw prob = 3/36 =1/12

Prob for getting same sum 4 in 3 rolls = $(\frac{1}{12} )^3$