Find two consecutive whole numbers whose product is 72.

1 answer:

3 0

$n(n+1)=72\\
n^2+n-72=0\\
n^2+9n-8n-72=0\\
n(n+9)-8(n+9)=0\\
(n-8)(n+9)=0\\
n=8 \vee n=-9\\\\
n+1=9 \vee n+1=-8
$

8 and 9 or -9 and -8

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