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AysviL [449]
3 years ago
5

Evaluate 8a + 3b - 10 + c^2 when a = 2,b = 5 and c = 4

Mathematics
1 answer:
Marianna [84]3 years ago
3 0

The answer to your problem is 37.

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For the geometric sequence of a1=2 and r=2 find a5
Brrunno [24]

Answer:

a_5 = 32

Step-by-step explanation:

The nth term for the geometric sequence is given by:

a_n = a_1 \cdot r^{n-1}

where,

a_1 is the first term

r is the common ratio

n is the number of terms.

As per the statement:

For the geometric sequence of a_1=2 and r=2

We have to find a_5

for n = 5;

a_5=a_1 \cdot r^{n-1}

Substitute the given values we have;

a_5 = 2 \cdot 2^4 = 2 \cdot 16

⇒a_5 = 32

Therefore, the value of a_5 is, 32

3 0
4 years ago
Please help me im being timed
Lady bird [3.3K]
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5 0
3 years ago
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The number of buttons an industrial button machine can manufacture each hour, y, varies directly with the number of active hours
-Dominant- [34]

Answer:

lol

Step-by-step explanation:

7 0
3 years ago
Tom bought 3 packages of Skittles for $1.25 each. How much did he spend?
polet [3.4K]

Answer:

Tom spent $3.75 of Skittles

Step-by-step explanation:

If each Skittle packet was $1.25, then if that is multiplied by 3, the product of the equation is, 3 dollars and 75 cents/$3.75

1.25 x 3 = 3.75

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3 years ago
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Lou has an account with $10,000 which pays 6% interest compounded annually. If to that account, Lou deposits $5,000 at the begin
katovenus [111]

Answer:

Option d. $22154 is the right answer.

Step-by-step explanation:

To solve this question we will use the formula A=P(1+\frac{r}{n})^{nt}

In this formula A = amount after time t

                        P = principal amount

                        r = rate of interest

                       n = number of times interest gets compounded in a year

                        t = time

Now Lou has principal amount on the starting of first year = 10000+5000 = $15000

So for one year A=15000(1+\frac{\frac{6}{100}}{1})^{1\times1}

= 15000(1+.06)^{1}

= 15000(1.06) = $15900

After one year Lou added $5000 in this amount and we have to calculate the final amount he got

Now principal amount becomes $15900 + $ 5000 = $20900

Then putting the values again in the formula

A=20900(1+\frac{\frac{6}{100}}{1})^{1\times1}

= 20900(1+.06)^{1}

= 20900(1.06)=22154

So the final amount will be $22154.

3 0
3 years ago
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