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3 years ago

6x^2-2x=0 find the roots

Mathematics

2 answers:

Snowcat [4.5K]3 years ago

7 0

Answer: The roots are 0 and 1/3

Step-by-step explanation:

The roots are also the x intercepts. Since this is a quadratic equation the points on the x axis are the roots. In this case the points are 0 and 1/3 since that is where the lines of the parabola pass through.

Lilit [14]3 years ago

6 0

Answer:

x = 0, x = $\frac{1}{3}$

Step-by-step explanation:

Given

6x² - 2x = 0 ← factor out 2x from each term

2x(3x - 1) = 0 ← in standard form

Equate each factor to zero and solve for x

2x = 0 ⇒ x = 0

3x - 1 = 0 ⇒ 3x = 1 ⇒ x = $\frac{1}{3}$

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ArbitrLikvidat [17]

Answer:

Step-by-step explanation:

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3 years ago

I learn maths and I don't know how to solve this problem.

Lyrx [107]

Answer:

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Step-by-step explanation:

In order for a limit to exists, the left side limit must exist and right side limit must exist and on top of that, they must be equal to each other.

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Rama09 [41]

6 (x+5)

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3 years ago

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Kay [80]

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tia_tia [17]

Answer:

10 Square Inches

Step-by-step explanation:

Trapezoid

Base =12 inches

Height =10 inches

Top side= 10 inches.

Area of a Trapezoid $=\frac{1}{2}(a+b)h, $where a and b are the lengths of the base and top respectively$$

$=\frac{1}{2}(10+12)*10\\=5*22=110 \:Square\:Inches$

Area of the Trapezoid=110 Square Inches

Rectangle

Base = 12 inches

Height =10 inches.

Area of a Rectangle=Base X Height

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Difference in Area between the two packages

Difference=Area of Rectangle-Area of Trapezoid

=120-110

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3 years ago

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