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3 years ago

The difference between a number divided by 3 and 4 is 20.

2 answers:

8 0

$*\\ x-\ number\\\\
\frac{x}{3}-4=20\ \ \ \ |Multiply\ by\ 3\\\\
x-12=20\ \ \ \ |Add\ 12\\\\
x=32\\\\Number\ is\ equal\ to\ 32.$

Alexxandr [17]3 years ago

7 0

Let, the number be "a"

Now, according to the question,
$\frac{a}{3} - 4=20$

$\frac{a-12}{3} =20$

$a-12 =20*3$

$a-12=60$

$a = 60 + 12$

$a = 72$

So, the number is 72

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Of the following mumbers,which one is prime 14,13,21,33

vfiekz [6]

The prime number is 13

4 0

3 years ago

Read 2 more answers

1. The probability of telesales representative making a sale on a customer call is 0.15.

Mumz [18]

Answer:

$n = 33$

$n = 19$

Step-by-step explanation:

From the question we are told that

The probability of telesales representative making a sale on a customer call is $p = 0.15$

The mean is $\mu = 5$

Generally the distribution of sales call made by a telesales representative follows a binomial distribution

i.e

$X \~ \ \ \ B(n , p)$

and the probability distribution function for binomial distribution is

$P(X = x) = ^{n}C_x * p^x * (1- p)^{n-x}$

Here C stands for combination hence we are going to be making use of the combination function in our calculators

Generally the mean is mathematically represented as

$\mu = n* p$

=> $5= n * 0.15$

=> $n = 33$

Generally the least number of calls that need to be made by a representative for the probability of at least 1 sale to exceed 0.95 is mathematically represented as

$P( X \ge 1) = 1 - P( X < 1 ) > 0.95$

=> $P( X \ge 1) = 1 - P( X =0 ) > 0.95$

=> $P( X \ge 1) = 1 - [ ^{n}C_0 * (0.15 )^0 * (1- 0.15)^{n-0}] > 0.95$

=> $1 - [1 * 1* (0.85)^{n}] > 0.95$

=> $[(0.85)^{n}] > 0.05$

taking natural log of both sides

$n = \frac{ln(0.05)}{ln(0.85)}$

=> $n = 19$

3 0

2 years ago

Find the volume of the triangular prism.<br> NEED ASAP PLS

Alexus [3.1K]

Answer:

32 inches cubed

Step-by-step explanation:

Multiply the length by the width: 4*4=16

Multiply by 12: 16*1/2=8

Multiply by height: 4*8=32

Hope this helped!

5 0

3 years ago

Read 2 more answers

A candy jar contains flavored jelly beans. There are 7 orange, 9 cherry, 3 lemon, 15 licorice, and 6 blueberry. Find the probabi

Alisiya [41]

Answer: 0.046

Step-by-step explanation:

From the question,

orange jelly beans= 7

Cherry jelly beans =9

Lemon jelly beans = 3

Licorice jelly beans = 15

Blueberry jelly beans = 6

Total jelly beans = 40

The probability of choosing the first cherry jelly beans will be = 9/40

After the first one is chosen, there'll be 8 cherry jelly beans and total of 39 left. The probability of choosing the second one will be = 8/39

The probability of choosing two cherry jelly beans in a row will be:

= 9/40 × 8/39

= 72/1560

= 0.046

4 0

3 years ago

Find y'(<img src="https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B3%7D" id="TexFormula1" title="\sqrt[3]{3}" alt="\sqrt[3]{3}" align="a

Bingel [31]

Given

2x³ + (x³ - 3) sin(2πy) - 3y = 0

we first notice that when x = ³√3, we get

2 (³√3)³ + ((³√3)³ - 3) sin(2πy) - 3y = 0

2•3 + (3 - 3) sin(2πy) - 3y = 0

6 - 3y = 0

3y = 6

y = 2

Differentiating both sides with respect to x gives

6x² + 3x³ sin(2πy) + 2π (x³ - 3) cos(2πy) y' - 3y' = 0

Then when x = ³√3, we find

6(³√3)² + 3(³√3)³ sin(2π•2) + 2π ((³√3)³ - 3) cos(2π•2) y' - 3y' = 0

6•³√9 + 3•3 sin(4π) + 2π (3- 3) cos(4π) y' - 3y' = 0

6•³√9 + 0 + 0 - 3y' = 0

3y' = 6•³√9

y' = 2•³√9

(that is, 2 times the cube root of 9)

8 0

2 years ago