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nikitadnepr [17]
3 years ago
5

Calculate the area of a quadrant of 7cm radius​

Mathematics
1 answer:
melomori [17]3 years ago
7 0

Answer:

38.5 square cm

Step-by-step explanation:

Central angle of Quadrant = 90°

area \: of \: quadrant =  \frac{90 \degree}{360 \degree} \times \pi {r}^{2}   \\  \\  =   \frac{1}{4} \times  \frac{22}{7}  \times  {7}^{2}   \\  \\  = \frac{1}{4} \times  22 \times  {7} \\  \\  =  \frac{77}{2}  \\  \\  = 38.5 \:  {cm}^{2}

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8.3*4 = 33.2 kg.
Hopefully that is correct
Since Yi Ting weighs 8.3 and her brother is 4 times heavier you would multiply those two numbers to get the answer.
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mariarad [96]

Answer:

B. (1, 0)

Step-by-step explanation:

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HOW DO I FIND QR<br><br> PLEASE HELP
Paul [167]

Solution: For finding QR we need to apply Pythagoras Theorem

What is Pythagoras Theorem ?

ans : Pythagoras Theorem is the sum of square of two sides which is equal to the third side or the hypotenuse. This formula is valid oy incase of Right-Angled Traingle because one of three angles here is 90°

According to this law let's apply it in the diagram shown here.

  • (Hypotenuse)² = (Adjacent)² + (Opposite)²

  • (PR)² = (QR)² + (PQ)²

  • (5x - 2)² = (QR)² + (3x - 1)²

  • (QR)² = (5x - 2)² - (3x - 1)²

After factorising both of them we get

  • (QR)² = 25x² - 20x + 4 - (9x² - 6x + 1)

  • (QR)² = 25x² - 20x + 4 - 9x² + 6x - 1

  • (QR)² = 16x² - 14x + 3

  • QR = √(16x² - 14x + 3)

So, QR is √(16x² - 14x + 3)

8 0
3 years ago
Help solve this I’m not sure if my answer was right. Pythagorean theorem.
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3 years ago
Keegan deposited $700 into his bank account. After one year, his bank account balance was $761.60. What interest rate did he ear
ikadub [295]

Answer:

8.8%

Step-by-step explanation:

We first divide the new amount by the original and close it with brackets.

Our one year will be shown as 1/1 as an indices

(761.60/700)^1/1

= 1.088

We then convert it to 0.088 and times it by 100.

0.088×100= 8.8% Compound interest rate.

This is correct as:

700×1.088= 761.6

Have a nice day! :)

7 0
3 years ago
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