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Naya [18.7K]
3 years ago
9

If anyone can answer this question... thank you so much! topic- Algebriac Expressions!

Mathematics
2 answers:
Svet_ta [14]3 years ago
5 0

Step-by-step explanation:

(2x-x^2+5)+(-4x-3+7x^2)-5

= {(-x^2+2x+5)+(7x^2-4x-3) }- 5

= {6x^2-2x+2}-5

= 6x^2-2x+2-5

= 6x^2-2x-3

nata0808 [166]3 years ago
4 0

Answer:

\huge{ \boxed{ \sf{ - 6 {x}^{2}  + 6x + 3}}}

Step-by-step explanation:

\underline{ \sf{ \:First ,\: Adding :  2x -  {x}^{2} + 5 \: and \:  - 4x - 3 + 7 {x}^{2}  }}

\sf{2x -  {x}^{2}  + 5 + ( - 4x - 3 + 7 {x}^{2} })

\text{Step \: 1} : In addition , sign of each term in the expression remains unchanged. Just remove the unnecessary parentheses.

\mapsto{ \sf{ - 2x -  {x}^{2}  + 5  - 4x - 3 + 7 {x}^{2} }}

\text{Step \: 2} : Collect like terms and simplify

Like terms are those which have the same base.

\mapsto{ \sf{ -  {x}^{2}  + 7 {x}^{2}  - 2x - 4x + 5 - 3}}

\underline{ \sf{Remember!}} :

  • The negative and positive integers are always subtracted but posses the sign of the bigger integer.
  • The negative integers are always added but posses the negative ( - ) sign.
  • The positive integers are always added and posses the positive ( + ) sign.

\mapsto{ \sf{6 {x}^{2}  - 6x + 2}}

\underline{ \sf{Now ,\: Subtracting \: 6 {x}^{2}  - 6x + 2 \: from \: 5}}

\sf{5 - (6 {x}^{2}  - 6x + 2)}

\text{Step \: 1} : While subtracting, sign of each term of the second expression changes.

\mapsto{ \sf{5 - 6 {x}^{2}  + 6x - 2}}

\mapsto{ \sf{ 5 - 2 - 6 {x}^{2}  + 6x}}

\text{step \: 2} :  \sf{Subtract \: 2 \: from \: 5}

\mapsto{ \sf{ 3 - 6 {x}^{2}  + 6x}}

Now, Rewrite the expression in standard form. That means , You have to arrange the terms having greatest power to lowest.

\mapsto{ \sf{ - 6 {x}^{2}  + 6x + 3}}

Hope I helped!

Best regards! :D

~\sf{TheAnimeGirl}

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