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liq [111]
4 years ago
13

Set V is all the unique three-digit numbers using the digits 1, 2, 3, 4, and 5. Which set would be considered a subset of set V?

Set W is all the unique three-digit numbers using the digits 1, 3, and 5. Set X is all the unique three-digit numbers using the digits 2, 4, and 6. Set Y is all the unique three-digit numbers using the digits 0, 2, and 4. Set Z is all the unique three-digit numbers using the digits 3, 5, and 7.
Mathematics
2 answers:
Temka [501]4 years ago
7 0

Answer:

A

Step-by-step explanation:

ed2020

Alborosie4 years ago
6 0

Answer: Choice A) Set W is all the unique three-digit numbers using the digits 1, 3, and 5

==========================================================

Explanation:

The original set uses the digits {1,2,3,4,5}. We can only use those digits. Nothing else. So that means we can't use 0, 2, 4, 6, or 7. This rules out choices B through D.

Only choice A is left. This answer choice involves 1,3 and 5 which is the correct subset of digits to use.

--------

Put another way, if set B was a subset of set A, then everything in B must also be found in A. Having B = {2,4,6} and A = {1,2,3,4,5} shows B is not a subset of A. We see a counter example has 6 in B, but not in set A.

This allows us to rule out choice B. Similar ideas apply to the answer choices C and D as well.

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liraira [26]

Answer:

Step-by-step explanation:

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5 0
3 years ago
In a basket, there are 7 male kittens and 5 female kittens. Donna randomly selects one, puts it back, and then randomly selects
andre [41]

We are given that

number of male kittens =7

number of female kittens =5

total number of kittens = number of male kittens + number of female kittens

total number of kittens = 7+5

total number of kittens = 12

now, we can find probability of selecting female kittens

P(female kittens)=(number of female kittens)/( total number of kittens)

P(female kittens) is

=\frac{5}{12}

now, we are given that

Donna randomly selects one, puts it back, and then randomly selects another

so, both probability are independent

so,

the probability that both selections were female kittens is

=P(female kittens)*P(female kittens)

now, we can plug values

the probability that both selections were female kittens is

=\frac{5}{12}\times \frac{5}{12}

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3 years ago
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Answer:

416.7

Step-by-step explanation:

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Bad White [126]

Answer:

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Step-by-step explanation:

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