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Svetlanka [38]
3 years ago
15

What does 24 divided by 1.5 equal.

Mathematics
2 answers:
Genrish500 [490]3 years ago
6 0
The answer to this question is 16
choli [55]3 years ago
3 0
16 would be the answer
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I don't understand what to write
natima [27]
4/5 = 1/5 + 3/5 is the only answer that I can think of. It's asking for the cumulative property of addition and that's all the information they give you

6 0
4 years ago
A kite has vertices at (2, 4), (5, 4), (5, 1), and (0, –1).
JulsSmile [24]
The answer is 16.8 units
7 0
3 years ago
Read 2 more answers
Can someone help me. I don't get this
Gala2k [10]
Last option — a decimal that terminates after three decimal places

Hope this helps good luck u can do thisss :)
4 0
3 years ago
A tank contains 60 kg of salt and 1000 L of water. Pure water enters a tank at the rate 6 L/min. The solution is mixed and drain
andrey2020 [161]

Answer:

dy/dt = 7y / (t − 1000)

Step-by-step explanation:

Change in mass of salt = mass of salt going in − mass of salt going out

dy/dt = 0 − (C kg/L × 7 L/min)

where C is the concentration of salt in the tank.

The concentration is mass divided by volume:

C = y / V

The volume in the tank as a function of time is:

V = 1000 + 6t − 7t

V = 1000 − t

Therefore:

C = y / (1000 − t)

Substituting:

dy/dt = -7y / (1000 − t)

dy/dt = 7y / (t − 1000)

If we wanted, we could separate the variables and integrate.  But the problem only asks that we find the differential equation, so here's the answer.

6 0
3 years ago
Suppose that the cost of a paving stone is $2.50 plus $.18 for every 4 in.³ of concrete how much would each paving stone cost ?
Dmitrij [34]
We need to know the dimension of the paving stone.

For example, the paving stone is shaped like a rectangular prism with the following dimension.

Length = 10 inches
Width = 3 inches
Height = 2 inches

Volume of a rectangular prism = Length * Width * Height
V = 10 in * 3 in * 2 in
V = 60 in³

60 in³ / 4 in³ = 15

cost of paving stone = 2.50 + .18(15) = 2.50 + 2.7 = 5.20 per paving stone.
3 0
3 years ago
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