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Naddik [55]
3 years ago
12

Square root of 90 to the nearest tenth

Mathematics
1 answer:
stellarik [79]3 years ago
8 0
9.5
is the square root of 90
rounded to the nearest tenth
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“Solve each inequality and graph its solution. Show work.”
Cloud [144]

Answer:

p or p >6

Step-by-step explanation:

Given

|-5-p| > 11

Required

Solve and graph

|-5-p| > 11

Remove absolute bracket

-5 - p > 11 or -5- p

Solve for p

-p > 11 + 5 or -p < -11 + 5

-p > 16 or -p < -6

Divide by -1

p or p >6

<em>See attachment for plot</em>

3 0
2 years ago
In a football or soccer game, you have 22 players, from both teams, in the field. what is the probability of having at least any
Tamiku [17]

We can solve this problem using complementary events. Two events are said to be complementary if one negates the other, i.e. E and F are complementary if

E \cap F = \emptyset,\quad E \cup F = \Omega

where \Omega is the whole sample space.

This implies that

P(E) + P(F) = P(\Omega)=1 \implies P(E) = 1-P(F)

So, let's compute the probability that all 22 footballer were born on different days.

The first footballer can be born on any day, since we have no restrictions so far. Since we're using numbers from 1 to 365 to represent days, let's say that the first footballer was born on the day d_1.

The second footballer can be born on any other day, so he has 364 possible birthdays:

d_2 \in \{1,2,3,\ldots 365\} \setminus \{d_1\}

the probability for the first two footballers to be born on two different days is thus

1 \cdot \dfrac{364}{365} = \dfrac{364}{365}

Similarly, the third footballer can be born on any day, except d_1 and d_2:

d_3 \in \{1,2,3,\ldots 365\} \setminus \{d_1,d_2\}

so, the probability for the first three footballers to be born on three different days is

1 \cdot \dfrac{364}{365} \cdot \dfrac{363}{365}

And so on. With each new footballer we include, we have less and less options out of the 365 days, since more and more days will be already occupied by another footballer, and we can't have two players born on the same day.

The probability of all 22 footballers being born on 22 different days is thus

\dfrac{364\cdot 363 \cdot \ldots \cdot (365-21)}{365^{21}}

So, the probability that at least two footballers are born on the same day is

1-\dfrac{364\cdot 363 \cdot \ldots \cdot (365-21)}{365^{21}}

since the two events are complementary.

8 0
3 years ago
WHAT IS "K" <br> 310 minus (30 times 7) = 5 times k
RSB [31]

Answer:

k = 20

Step-by-step explanation:

310-(30x7) = 5k

310-210=5k

100=5k

 /5   /5

20=k

7 0
3 years ago
Can 1,2,5 form a right triangle​
malfutka [58]
No 1+2=3 which is less than 5
The two sides must equal more than the third one when added
8 0
3 years ago
Olivia wants to use her leftover yarn to create a blanket for her friend. She has 11
Leokris [45]

Answer:

she need 16 purple yard to use for blanket

7 0
2 years ago
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