Answer:
x= 24
Step-by-step explanation:
open the bracket
4×3x =12x + 4 × 2 =8
12×+ 8-6×6
12×+ 12
x= 24
Answer:
Height of tree is 
<em>15 m.</em>
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Step-by-step explanation:
Given that student is 20 m away from the foot of tree.
and table is 1.5 m above the ground.
The angle of elevation is: 34°28'
Please refer to the attached image. The given situation can be mapped to a right angled triangle as shown in the image.
AB = CP = 20 m
CA = PB = 1.5 m
= 34°28' = 34.46°
To find TB = ?
we can use trigonometric function tangent to find TP in right angled 
Now, adding PB to TP will give us the height of tree, TB
Now, height of tree TB = TP + PB
TB = 13.72 + 1.5 = 15.22 <em>15 m</em>
Answer:
The personal hygiene part of the store (I think)
Step-by-step explanation:
This is an ultimately weird question, so I don't really know. But my answer is what I think, (I don't even know if it exists though).
The answer is D) 72, 108
First you have to find out the measure of the two other angles in the triangle. Those two angles will be equivalent.
Because the sum of all three angles in a triangle is 180, you subtract 36 from it (180 - 36 = 144) then divide by 2 (144/2 = 72).
So, the two angles at the bottom of the triangle are each 72. Because those angles are supplementary to the angles at the top of the trapezoid, you subtract 72 from 180 (180 - 72 = 108).
108 + 108 = 216
The sum of all the angles in a trapezoid is 360, so subtract 216 from 360 (360 - 216 = 144) then divide by 2 (144/2 = 72)
Answer:
5832 ways
Step-by-step explanation:
Since the circle has 8 sectors and there is 4 colour,
Assuming the sectors are numbered 1 to 8,
Sector 1 : can be coloured with any of the 4 colour in 4 ways
Sector 2 can be coloured with any of the remaining 3 colours in 3 ways
Sector 3 in 3 ways without using the colour in sector 2
Sector 4 in 3 ways without using the colour in sector 3
Sector 5 in 3 ways without using the colour in sector 4
Sector 6 in 3 ways without using the colour in sector 5
Sector 7 in 3 ways without using the colour in sector 6
Sector 8 in 2 ways without using the colours in sector 1 and 7
Number of ways of colouring = 4*3*3*3*3*3*3*2 = 5832 ways
