Question

Find the area of a sector with a central angle of 32° and a radius of 8.5 millimeters. Round to the nearest tenth.

Answer 1

You use the formula:
A = angles/360*pi*r^2
A = 32/360pi*8.5^2 = 0.279* 72.25= 20.15775 rounded to 20.2
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Answer 2

Answer:

The area of sector is 20.2 millimeter².

Step-by-step explanation:

The formula for area of sector is

$A=\pi r^2\times (\frac{\theta}{360})$

The central angle of the sector is 32° and the radius of the circle is 8.5 millimeters.

$A=\pi\times (8.5)^2\times (\frac{32}{360})$

$A=\pi\times (6.42222222222)$

$A=20.1760061531$

$A\approx 20.2$

Therefore the area of sector is 20.2 millimeter².