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4 years ago

Kenny's weight is 6/7 times melvin's weight. what is the ratio of melvin's weight to the total weight of the two boys?

2 answers:

4 0

Answer=7:13

Kenny's Weight*6/7=Melvin's Weight

So, for example, if Melvin's weigh was 7...

Kenny's Weight*6/7=7
divide both sides by 6/7
Kenny Weight=6

So we can say that Melvin's weight to Kenny's weight is 7:6

The boys total weights would be...
7+6=13

So Melvin's weight over the total weight of the two boys is:

7:13

Mademuasel [1]4 years ago

4 0

Answer:

$\frac{7}{13}$

Step-by-step explanation:

Let

x------> Melvin's weight

y------> Kenny's weight

we know that

$y=\frac{6}{7}x$

$x+y=x+\frac{6}{7}x=\frac{13}{7}x$ -----> total weight of the two boys

Find the ratio of Melvin's weight to the total weight of the two boys

$ratio=\frac{x}{(\frac{13}{7}x)} =\frac{7}{13}$

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