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4 years ago

Kenny's weight is 6/7 times melvin's weight. what is the ratio of melvin's weight to the total weight of the two boys?

2 answers:

4 0

Answer=7:13

Kenny's Weight*6/7=Melvin's Weight

So, for example, if Melvin's weigh was 7...

Kenny's Weight*6/7=7
divide both sides by 6/7
Kenny Weight=6

So we can say that Melvin's weight to Kenny's weight is 7:6

The boys total weights would be...
7+6=13

So Melvin's weight over the total weight of the two boys is:

7:13

Mademuasel [1]4 years ago

4 0

Answer:

$\frac{7}{13}$

Step-by-step explanation:

Let

x------> Melvin's weight

y------> Kenny's weight

we know that

$y=\frac{6}{7}x$

$x+y=x+\frac{6}{7}x=\frac{13}{7}x$ -----> total weight of the two boys

Find the ratio of Melvin's weight to the total weight of the two boys

$ratio=\frac{x}{(\frac{13}{7}x)} =\frac{7}{13}$

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Solution

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- We are required to find the volume of the cylinder and the cube and then use the results to find the volume of the composite figure.

- The formulas needed for this calculation are:

$\begin{gathered} Volume\text{ of Cylinder}=\pi\times r^2\times h \\ where, \\ r=radius\text{ of the cylinder} \\ h=height\text{ of the cylinder} \\ \\ Volume\text{ of Cube}=l^3 \\ where, \\ l=dimension\text{ of the cube} \\ \\ Volume\text{ of Composite figure}=Volume\text{ of Cylinder }+Volume\text{ of Cube} \\ \end{gathered}$

- With the information above, we can proceed to solve the question

Volume of the Cylinder:

$\begin{gathered} V=\pi\times r^2\times h \\ r=\frac{6}{2}=3\text{ \lparen Since 6cm is the diameter of the cylinder\rparen} \\ h=4 \\ \\ \therefore V=\pi\times3^2\times4 \\ \\ V=36\pi cm^3 \end{gathered}$

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$\begin{gathered} V=l^3 \\ l=9 \\ \therefore V=9^3=729cm^3 \end{gathered}$

Volume of Composite Figure:

$\begin{gathered} V=36\pi+729 \\ use\text{ }\pi=3.14 \\ \\ V=36\left(3.14\right)+729 \\ \\ V=842.04cm^3 \end{gathered}$

Final Answer

The volume of the composite shape is 842.04 cm³

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