Answer:
Jenny save 4 times
for the month
Step-by-step explanation:
Given Jenny has saved
over the last 12 months.
She saved either
or
a month.
Let the number of months to save
be x
Let the number of months to save
be y
Total period is 12 month.

Jenny has saved $3,800 over the last 12 months.

Dividing both side from 50 we get,


Now Multiplying equation 1 by 5 we get,

Now Subtracting Equation 3 by equation 2 we get,

Substituting the value of y in equation 1 we get,

∴ Jenny save 4 Months of
and 8 Months of
in a 12 month duration