Gauge employee <span>performance thank you and have a nice week</span>
Using the probability concept, it is found that:
P(board-certified or teacher) = 0.8462.
<h3>What is a probability?</h3>
A probability is given by the <u>number of desired outcomes divided by the number of total outcomes</u>.
Researching the problem on the internet, it is found that:
- There is a total of 10 + 6 + 5 + 18 = 39 professionals.
- Of those, 15 are board-certified, plus 18 that are non-board certified teachers, hence the number of desired outcomes is 33.
Then:
Hence:
P(board-certified or teacher) = 0.8462.
You can learn more about the probability concept at brainly.com/question/15536019
Assume all conditions for inference have been met, based on the confidence interval, the claim that is supported is that;
More than half of all people prefer texting.
<h3>Understanding Confidence Intervals</h3>
We are given;
Confidence Level; CL = 95%
Margin of error; MOE = 3%
Since 56 percent of the respondents prefer to use cell phones for texting rather than for making phone calls. It means that; x' = 56%
Thus;
CI = x' ± MOE
CI = 56% ± 3%
CI = 53% OR 59%
Thus, in conclusion we can say that more than half of the people prefer texting
Read more about Confidence Intervals at; brainly.com/question/17097944
<h3>
Answer:</h3>
60 days
<h3>
Explanation:</h3>
Half-life is the amount of time it takes half of a substance to decay away.
Guess and Check
One method for solving half-life problems like this is to guess and check. To do this, we can continue to divide 475mg by 2 until we get to 30mg.
- 475 ÷ 2 = 237.5
- 237.5 ÷ 2 = 118.75
- 118.75 ÷ 2 = 59.375
- 59.375 ÷ 2 = 29.6875
As seen here, it takes approximately 4 half-lives for this sample of Ra-225 to decay to 30mg. Now, we can multiply 4 by the length of the half-life, 15 days.
Fractions
Another way to solve this is to use fractions.
- 16 is equivalent to .
This means that it takes 4 half-lives for 475mg to decay to 30mg. Using the same method above, we can tell that 4 half-lives are 60 days.
Important Note
In this question, I rounded occasionally. So, not all of the values are exact, but they are all very close.