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Alinara [238K]
3 years ago
15

Write an algebraic expression for 9 more than 2 multiplied by f

Mathematics
2 answers:
seropon [69]3 years ago
5 0

Answer:

2f+9

Step-by-step explanation:

hope this helps

irinina [24]3 years ago
4 0

Answer:

2f+9

Step-by-step explanation:

First identify the expression for anything such as "less than" or "more than". If there is the whole expression will be flipped.

(Example)

A expression has a "less than" in it.

4f-3

This will turn to 3-4f

_____________________________

Since this has a "More than", whatever you get as your expression will be flipped.

So, the "more" is addition. "Multiplied" is multiplication. So, the expression will be

9+2f

But because of "more than, it will be

2f+9

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a. Fill in the midpoint of each class in the column provided. b. Enter the midpoints in L1 and the frequencies in L2, and use 1-
Tresset [83]

Answer:

\begin{array}{ccc}{Midpoint} & {Class} & {Frequency} & {64} & {63-65} & {1}  & {67} & {66-68} & {11} & {70} & {69-71} & {8} &{73} & {72-74} & {7}  & {76} & {75-77} & {3} & {79} & {78-80} & {1}\ \end{array}

Using the frequency distribution, I found the mean height to be 70.2903 with a standard deviation of 3.5795

Step-by-step explanation:

Given

See attachment for class

Solving (a): Fill the midpoint of each class.

Midpoint (M) is calculated as:

M = \frac{1}{2}(Lower + Upper)

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Lower \to Lower class interval

Upper \to Upper class interval

So, we have:

Class 63-65:

M = \frac{1}{2}(63 + 65) = 64

Class 66 - 68:

M = \frac{1}{2}(66 + 68) = 67

When the computation is completed, the frequency distribution will be:

\begin{array}{ccc}{Midpoint} & {Class} & {Frequency} & {64} & {63-65} & {1}  & {67} & {66-68} & {11} & {70} & {69-71} & {8} &{73} & {72-74} & {7}  & {76} & {75-77} & {3} & {79} & {78-80} & {1}\ \end{array}

Solving (b): Mean and standard deviation using 1-VarStats

Using 1-VarStats, the solution is:

\bar x = 70.2903

\sigma = 3.5795

<em>See attachment for result of 1-VarStats</em>

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