Which criteria for triangle congruence can be used to prove the pair of triangles below are congruent?
2 answers:
Answer: The correct option is fourth, i.e., SSS.
Explanation:
First write the name of vertices as shown below,
From the figure we can say that in triangle DAB and triangle BCD,
In both triangle the sides BD is common, so,
Since three sides of triangles DAB and triangle BCD are same so by the SSS property of congruent triangle we can conclude that the triangle DAB and triangle BCD are congruent.
Therefore the fourth option is correct.
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Answer:
Step-by-step explanation:
Given
Represent Babysitting with B
Represent Gas Station with G
Total workhours = At most 15
Earnings = At least $90
First, we need to represent the work hours as inequality
B + G = At most 15
At most 15 means less than or equal to 15.
So, we have:
Next, we represent the earnings as inequality.
6 hours of babysitting is: 6B
10 hours at gas station is: 10G
So:
6B + 10G is at least 90
At least 90 means greater than or equal to 90
So, we have:
Answer:
Step-by-step explanation:
Given: There are 2 classes of 25 students.
13 play basketball
11 play baseball.
4 play neither of sports.
Lets assume basketball as "a" and baseball as "b".
We know, probablity dependent formula; P(a∪b)= P(a)+P(b)-p(a∩b)
As given total number of student is 25
Now, subtituting the values in the formula.
⇒P(a∪b)=
taking LCD as 25 to solve.
⇒P(a∪b)=
∴ P(a∪b)=
Hence, the probability that a student chosen randomly from the class plays both basketball and baseball is .