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docker41 [41]
3 years ago
15

Jasmine was shopping at a go wet store and saw the following list of prices. She brought $20 to spend on groceries. If she buys

4 boxes of cereal and 2 liters of soda, how much money will she have left? 3 boxes of pasta $18, 2 boxes of cereal $4.50, 4 liters of soda $8.40, 2 bags of apples $6. Plz I will give you 100 points
Mathematics
2 answers:
Nookie1986 [14]3 years ago
6 0

4 boxes of cereal: $9

2 liters of soda: $4.20

total: $13.20

She will have $6.80 left

SashulF [63]3 years ago
5 0

First, let's find the price of the 4 boxes of cereal. By hypothesis, 2 boxes of cereal cost $4.50. So 4 boxes will cost 2*4.50 = $9.

4 liters of soda costs $8.40. Jasmine bought 2 liters, which is half of the stated amount and price. So the price of 2 liters of soda is 8.40/2 = $4.20

So in total, Jasmine had to pay 9+4.20 = $13.2

She had $20 in her pocket. So she still have 20-13.2 = $6.8

Hope this helps! :)

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Store A sells a case of 18 bottles for $10. Store B sells a case of 12 bottles for $6. Which store sells the drinks for less?
jek_recluse [69]
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Is 23in bigger than 2ft
Helga [31]
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Drew has two cats. One cat weighs 17 pounds, and the other one weighs 1212 pounds. Audrey's dog weighs 33 pounds. What is the di
wolverine [178]

Answer:

64 ounces.

Step-by-step explanation:

Given:

Drew has two cats.

One cat weighs 17 pounds.

The other one weighs 12 pounds. (instead of 1212 pounds)

Audrey's dog weighs 33 pounds.

Question asked:

What is the difference in ounces between Audrey's dog and the combined weights of Drew's cats ?

Solution:

<u>For Drew </u>

Weight of one cat = 17 pounds

Weight of another cat = 12 pounds

Combined weight = 17 pounds + 12 pounds = 29 pounds

Now, convert it into ounces:-

As we know:

1 pound = 16 ounces

29 pounds = 16 \times 29 = 464 ounces

<u>For Audrey</u>

Weight of dog = 33 pounds

Now, convert it into ounces:-

1 pound = 16 ounces

33 pounds = 16 \times 33 = 528 ounces

Combined weight of Drew's cats = 464 ounces

Weight of Audrey's dog = 528 ounces

Difference = 528 ounces - 464 ounces = 64 ounces

Thus,  the difference in ounces between Audrey's dog and the combined weights of Drew's cats is of 64 ounces.

<u></u>

5 0
3 years ago
In a large section of a statistics​ class, the points for the final exam are normally​ distributed, with a mean of 71 and a stan
kumpel [21]

Answer:

The lowest score on the final exam that would qualify a student for an​ A is 80.

The lowest score on the final exam that would qualify a student for a B is 74.68.

The lowest score on the final exam that would qualify a student for a C is 67.33.

The lowest score on the final exam that would qualify a student for a​ D is 62.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Mean of 71 and a standard deviation of 7.

This means that \mu = 71, \sigma = 7

Grades are assigned such that the top​ 10% receive​ A's, the next​ 20% received​ B's, the middle​ 40% receive​ C's, the next​ 20% receive​ D's, and the bottom​ 10% receive​ F's.

This means that:

90th percentile and above: A

70th percentile and below 90th: B

30th percentile to the 70th percentile: C

10th percentile to the 30th: D

Lowest score for an A:

Top 10% receive A, which means that the lowest score that would qualify a student for an A is the 100 - 10 = 90th percentile, which is X when Z has a pvalue of 0.9, so X when Z = 1.28.

Z = \frac{X - \mu}{\sigma}

1.28 = \frac{X - 71}{7}

X - 71 = 7*1.28

X = 80

The lowest score on the final exam that would qualify a student for an​ A is 80.

Lowest score for a B:

70th percentile, which is X when Z has a pvalue of 0.7, so X when Z = 0.525.

Z = \frac{X - \mu}{\sigma}

0.525 = \frac{X - 71}{7}

X - 71 = 7*0.525

X = 74.68

The lowest score on the final exam that would qualify a student for a B is 74.68.

Lowest score for a C:

30th percentile, which is X when Z has a pvalue of 0.3, so X when Z = -0.525.

Z = \frac{X - \mu}{\sigma}

-0.525 = \frac{X - 71}{7}

X - 71 = 7*(-0.525)

X = 67.33

The lowest score on the final exam that would qualify a student for a C is 67.33.

Lowest score for a D:

10th percentile, which is X when Z has a pvalue of 0.1, so X when Z = -1.28.

Z = \frac{X - \mu}{\sigma}

-1.28 = \frac{X - 71}{7}

X - 71 = 7*(-1.28)

X = 62

The lowest score on the final exam that would qualify a student for a​ D is 62.

4 0
3 years ago
Can somebody tell me the answers to this ??? pleaseeee !!!
kolbaska11 [484]
90^2-54^2=5184
root 5184=72
pr=72

3 0
3 years ago
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