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Alekssandra [29.7K]
3 years ago
14

Sally and her friend Lucie started saving money for their vacation on the same day. Sally started with $150 and plans to add $5

to the total every week. Lucie started with $200 and plans to add $3 to the total every week. After how many weeks will their savings be the same?
Mathematics
1 answer:
solniwko [45]3 years ago
5 0

Answer:

Their savings will be same after 25 weeks.

Step-by-step explanation:

The difference in both person's saving is $ 2/week

$5-$3=$2

The total difference in the starting point is $50 if we divide $50 by $2 we will get a number of 25 which is the number of weeks it will take both savings to reach at a same level

Calculation:

Starting point $150

Savings $5/week

5*25+150= $275

Starting point: $200

Savings 3$/week

3*25+200= $275

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Cal is measuring temperature changes in four substances over different time periods as part of a school project. Which data show
djyliett [7]

Answer:

C) The third table. K= 5

C)\frac{10}{2}=\frac{15}{3}=\frac{25}{5}=\frac{40}{8}=k= 5

Step-by-step explanation:

1) Below there are the missing data:

A proportional relationship through a constant k. It is obtained when we divide:

k=\frac{y}{x}

2)In this case, when we divide the temperature (T) by the time (h).

k=\frac{T}{h}

3)So, examining the table below we are searching for a ratio k common to all measures (temperatures over hour).

A) \frac{12}{3}\neq\frac{25}{5}\neq\frac{36}{6}\neq\frac{81}{9}\\B) \frac{22.5}{3}\neq\frac{30}{4}\neq\frac{52.5}{7}\neq\frac{67.5}{8}\\C)\frac{10}{2}=\frac{15}{3}=\frac{25}{5}=\frac{40}{8}=k= 5\\D)\frac{8.5}{2}\neq\frac{22.5}{5}\neq\frac{28.5}{7}\neq\frac{36}{8}

3 0
3 years ago
If the outliers are not included, what is the mean of the data set?
Aleksandr-060686 [28]
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What is the equation for a 75 90 15 triangle​
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Answer:

30,60,90  triangle, which is the lengths  1      √ 3 , and  2   respectively. This is what I have got so far: Using the 30-60-90 Ratio

Step-by-step explanation:

4 0
4 years ago
The answer to this word problem usinf discriminant
solniwko [45]
\bf h=-9.8t^2+45t+1.2\implies 64.5=-9.8t^2+45t+1.2
\\\\\\
0=-9.8t^2+45t-63.3\\\\
-------------------------------

\bf \qquad \qquad \qquad \textit{discriminant of a quadratic}
\\\\\\
0=\stackrel{\stackrel{a}{\downarrow }}{-9.8}t^2\stackrel{\stackrel{b}{\downarrow }}{+45}t\stackrel{\stackrel{c}{\downarrow }}{-63.3}
~~~~~~
\stackrel{discriminant}{b^2-4ac}=
\begin{cases}
0&\textit{one solution}\\
positive&\textit{two solutions}\\
negative&\textit{no solution}
\end{cases}
\\\\\\
(45)^2-4(-9.8)(-63.3)\implies -456.36

the discriminant is a negative value, thus no solution for such quadratic, meaning if we use h=64.5 like we did, there's no "t" seconds at which point the ball hits the batting cage.
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