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laiz [17]
3 years ago
7

Which set of side lengths defines a right triangle?

Mathematics
2 answers:
scoundrel [369]3 years ago
7 0


B. 5,12,13.

5^2=25  12^2=144. 13^2=169

a^2+b^2=c^2.

a=5 b=12 c=13

25+144=169

Snowcat [4.5K]3 years ago
4 0
In a right triangle, the square of the largest side is equal to the sum of the squares of the smaller sides, so if you plug the sides in to that equation, you should get zero if those sides form a right triangle.
B is the only option where this is true, so I believe set B defines a right triangle.
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(-5+1)(((3+6)*2-2)(5)-1) evaluate. ​
Anuta_ua [19.1K]

Answer:

-316

Step-by-step explanation:

Each operation shown in bold is done on the next line.

(-5+1)(((3+6)*2-2)(5)-1) =

= (-4)((9*2-2)(5)-1)

= (-4)((18-2)(5)-1)

= (-4)(16(5)-1)

= (-4)(80-1)

= (-4)(79)

= -316

8 0
3 years ago
Mr Ramirez receives blueprints
densk [106]
Uhhh
Could you finish the question?
6 0
3 years ago
A.(x-6, y-5). B.(x.-5, y-6) c.(x+5, y+6). D.(x+ 6, y+5)
Svet_ta [14]

Answer:

c. (x+5, y+6)

6 0
3 years ago
Read 2 more answers
(4.2.24) One design for a system requires the installation of two identical components. The system will work if at least one of
lesantik [10]

Answer:

<em>The second design has a greater probability of functioning than the first one</em>

Step-by-step explanation:

<u>Probabilities</u>

The probability that a component works is 0.9. We need to evaluate two options to find the arrangement that provides the greatest probability for the system to function.

The first option is to install two identical components and consider if at least one of them works, the system will work. Let's call W to the event in which one component works, and N if it doesn't.

Choosing two components, we can have the following outcomes

\Omega=\{WW,WN,NW,NN\}

The first 3 of the outcomes will make the system work. Only the last one is not acceptable. Knowing the probability of the component to work is p=0.9, the negated probability is 1-0.9=0.1. The probability of NN is

P(NN)=0.1^2=0.01

Thus, the probability that the system works is 1-0.01=0.99 or 99%

Now for the second option, we have 4 components. There are 24 possible outcomes from which we can accept only those who have at least two W's, that is {WWNN,WWWN,WWWW} or any equivalent combination regardless of the order of appearance.

To calculate the probability of such arrangements, we'll use the binomial distribution formula

\displaystyle P(n,k,p)=\binom{n}{k}p^kq^{n-k}

Where q=1-p, n=4 and k is the number of W in the combination. We have

\displaystyle P(4,2,0.9)=\binom{4}{2}0.9^2q^{2}=0.0486

\displaystyle P(4,3,0.9)=\binom{4}{3}0.9^3q^{1}=0.2916

\displaystyle P(4,4,0.9)=\binom{4}{4}0.9^4q^{0}=0.6561

The total probability is

P(WWNN,WWWN,WWWW)=0.9963=99.63%

The second design has a greater probability of functioning than the first one

4 0
3 years ago
Mark earns $550.00 per month. If he spends
kap26 [50]

Answer:

40%

Step-by-step explanation:

Find the percent by dividing 220 by 550

220/550

= 0.4

So, he spends 40% of his monthly income on gas

7 0
3 years ago
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