( B) ∠OSN is the correct answer.
As we know two angles are Supplementary if sum of that two angles is 180° or they form a linear pair
The meaning of linear pair is that the two angles should be such that the non common arms should lie on opposite side of the common arm and at the point of intersection of two angles have the same vertex. Also the two non common arms should form a line.
SO IF ONE ∠ IS Ф° OTHER SHOULD BE 180-Ф°. FOR EXAMPLE ON ∠ IS 60° OTHER WILL BE 180-60°=120°
Supplement of
1.45°=135°
2.70°=110°
Step-by-step explanation:
The area would be 9 times compared to the area of the original square. To test this, you can let the side of the original square be equal 1. By tripling this side, the side becomes three. Utilizing the area of a square formula, A= s^2, the area of the original square would be 1 after substituting 1 for s. Then, you do the same for the area of the tripled square. With the substitution, the area of the tripled square would be 9. This result displays the area of the tripled square being 9 times as large as the area of the original square. This pattern can be used for other measurements of the square such as:
let s = 2, Original Area= 2^2 = 4 Tripled Area= (2(3))^2 = 6^2= 36. 36/4 = 9
let s = 3, Original Area = 3^2 = 9 Tripled Area - (3(3))^2 = 9^2 =81. 81/9 = 9
let s = 4, Original Area = 4^2 = 16 Tripled Area - (4(3))^2 = 12^2 = 144. 144/16 = 9
let s = 5, Original Area = 5^2 = 25 Tripled Area - (5(3))^2 = 15^2 = 225. 225/25 = 9
let s = 6, Original Area = 6^2 = 36 Tripled Area - (6(3))^2 = 18^2 = 324. 324/36 = 9
let s = 7, Original Area = 7^2 = 49 Tripled Area - (7(3))^2 = 21^2 = 2,401. 2,401/49 = 9
You can continue to increase the length of the square and follow this pattern and it will be consistent.
The formula for the perimeter of a square is P = 4s, where s is the length of one of the four (4) congruent sides of the square.
The formula for the area of a square is A = s², and we're given that the area of a square, whose perimeter we're trying to find, is 36 sq. units; therefore, we have:
A = s²
36 sq. units = s²
√(36 sq. units) = √s²
6 units = s (Note: We used the positive square root (6) rather than the negative square root (-6) since you physically can't have a negative length!)
Therefore, ...
P = 4s
P = 4(6 units)
P = 24 units is the perimeter of a square whose area is 36 square units
Answer:
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Step-by-step explanation:
The answer to your question is 29/250
