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2 years ago

10

I’m on the verge of a mental breakdown.

1 answer:

dangina [55]2 years ago

4 0

this equation just multiplied my depression by 2 omg im so sorry dawg .

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A grocery store polls every twentieth customer to determine if they are satisfied with the cleanliness of the store. Forty custo

Helga [31]

26/40=65% of customers
65% of 800 customers=520 who think the store is clean enough

4 0

1 year ago

<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7Bx%20%5Csqrt%7Bx%20%5Csqrt%7Bx%20%5Csqrt%7Bx....%7D%20%7D%20%7D%20%7D%20%20%3D%20%

andrey2020 [161]

First observe that if $a+b>0$ ,

$(a + b)^2 = a^2 + 2ab + b^2 \\\\ \implies a + b = \sqrt{a^2 + 2ab + b^2} = \sqrt{a^2 + ab + b(a + b)} \\\\ \implies a + b = \sqrt{a^2 + ab + b \sqrt{a^2 + ab + b(a+b)}} \\\\ \implies a + b = \sqrt{a^2 + ab + b \sqrt{a^2 + ab + b \sqrt{a^2 + ab + b(a+b)}}} \\\\ \implies a + b = \sqrt{a^2 + ab + b \sqrt{a^2 + ab + b \sqrt{a^2 + ab + b \sqrt{\cdots}}}}$

Let $a=0$ and $b=x$ . It follows that

$a+b = x = \sqrt{x \sqrt{x \sqrt{x \sqrt{\cdots}}}}$

Now let $b=1$ , so $a^2+a=4x$ . Solving for $a$ ,

$a^2 + a - 4x = 0 \implies a = \dfrac{-1 + \sqrt{1+16x}}2$

which means

$a+b = \dfrac{1 + \sqrt{1+16x}}2 = \sqrt{4x + \sqrt{4x + \sqrt{4x + \sqrt{\cdots}}}}$

Now solve for $x$ .

$x = \dfrac{1 + \sqrt{1 + 16x}}2 \\\\ 2x = 1 + \sqrt{1 + 16x} \\\\ 2x - 1 = \sqrt{1 + 16x} \\\\ (2x-1)^2 = \left(\sqrt{1 + 16x}\right)^2$

(note that we assume $2x-1\ge0$ )

$4x^2 - 4x + 1 = 1 + 16x \\\\ 4x^2 - 20x = 0 \\\\ 4x (x - 5) = 0 \\\\ 4x = 0 \text{ or } x - 5 = 0 \\\\ \implies x = 0 \text{ or } \boxed{x = 5}$

(we omit $x=0$ since $2\cdot0-1=-1\ge0$ is not true)

3 0

1 year ago

1. If Ray ran 10.5 miles in 7 days, how many miles

Rama09 [41]

Jsjsjsjkssiisisisosisisisksk

8 0

2 years ago

Read 2 more answers

Add the equations.<br>2x-3y = -1<br>+ 3x + 3y= 26<br><br>

hichkok12 [17]

Answer:

The answer in the procedure

Step-by-step explanation:

we have

2x-3y=-1 ----> equation A

3x+3y=26 --> equation B

Solve the system by elimination

Adds equation A and equation B

2x-3y=-1

3x+3y=26

----------------

2x+3x=-1+26

5x=25

x=25/5

x=5

Find the value of y

substitute the value of x in equation A or equation B and solve for y

2(5)-3y=-1

10-3y=-1

3y=10+1

y=11/3

8 0

2 years ago

Find dy /dx of x² - 2x + 5 - 6x

BaLLatris [955]

Answer:

Step-by-step explanation:

If $y=x^2-2x+5-6x$ then

$y=x^2-8x+5$ by combining like terms. (I'm thinking you might have mistyped the problem because this representation is weird).

$\frac{dy}{dx}=2x-8$

6 0

3 years ago