Answer:
400 ft
Step-by-step explanation:
Let the distance traveled = d
Let the time taken = t
d α t^2
d = kt^2
k = d /t^2
When d = 100 and t = 2.5secs
k = 100/ (2.5)^2
k = 16
d = 16t^2
When t = 5secs
d = 16(5)^2
d = 16 * 25
d = 400 ft
Combinations of 7 taken 4 at a time.
C (7,4) = 7! /[ 4!(3!)]
7 x 6 x 5 = 210
210 divided by 3 = 70
70 divided by 2 = 35
We know that
At sea level, the height is 0 and
the pressure is 98 kilopascals
At 1000 ft, the height is 1000 and
the pressure <span>decreases about 11.41%
</span>i(100%-11.41%)/100----> (0.8859)
therefore
1) at 1000 ft--------> the pressure is 98*(0.8859)----------> 86.82 kilopascals
2) at 2000 ft--------> the pressure is 86.82*(0.8859)-------> 76.91 kilopascals
3) at 3000 ft--------> the pressure is 76.91*(0.8859)-------> 68.14 kilopascals
4) at 4000 ft---------> the pressure is 68.14*(0.8859)-------> 60.36 kilopascals
the answer is
<span>The pressure at an altitude of 4000 m is about </span>60.36 kilopascals
The answer would be 8746 ft :)
