Answer:
(-2, 18), (0, 10), (2, 2)
Step-by-step explanation:
All you do is plug each coordinate into the equation to confirm the authentication.
I am joyous to assist you anytime.
First step you should do is s<span>implify both sides of your equation:
</span>29-(x+8)=6x-7
Distribute the Negative Sign:
29+-1(x+8)=6x-7
29+-1x+(-1)(8)=6x-7
29+-x+-8=6x-7
29+-x+-8=6x+-7
<span>Combine Like Terms:
</span>(-x)+(29+-8)=6x-7
-x+21=6x-7
<span>Subtract 6x from both sides:
</span>-x+21-6x=6x-7-6x
-7x+21=-7
<span>Subtract 21 from both sides:
</span>-7x+21-21=-7-21
-7x=-28
<span>Divide both sides by -7:
</span>-7x/-7 = -28/-7
And now your answer should be:
x=4
~~~~~
Good luck~ Sans
Answer:
2
Step-by-step explanation:
slope = (difference in y)/(difference in x)
slope = (7 - 3)/(4 - 2)
slope = 4/2 = 2
Answer: 2
Answer:
y=−x−1/3x−8
Step-by-step explanation:
y=8x−1/3x+1
To find the inverse function, swap x and y, and solve the resulting equation for x.
If the initial function is not one-to-one, then there will be more than one inverse.
So, swap the variables: y=8x−1/3x+1 becomes x=8y−1/3y+1.
Now, solve the equation x=8y−1/3y+1 for y.
y=−x−1/3x−8
Sorry I was in a rush and couldn't do the fractions as formulae. Hope it helped anyways.
Answer:
The values of 
so that 
have vertical asymptotes are 
, 
, 
, 
, 
.
Step-by-step explanation:
The function cosecant is the reciprocal of the function sine and vertical asymptotes are located at values of so that function cosecant becomes undefined, that is, when function sine is zero, whose periodicity is . Then, the vertical asymptotes associated with function cosecant are located in the values of of the form:
, 
In other words, the values of so that have vertical asymptotes are , , , , .
