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Kitty [74]
4 years ago
7

2,058 in expended form

Mathematics
2 answers:
irga5000 [103]4 years ago
5 0

Answer:

2000 + 50 + 8

Step-by-step explanation:

irina [24]4 years ago
3 0

Answer:

2000+50+8

Step-by-step explanation:

Since our number is 2,058, we need to break it up using place value. We know there is a 2 in the thousands, creating 2000. There is nothing in the hundreds, so we don't need to write anything there. There is a 5 in the tens to create 50, and finally there is an 8 in the ones place to make 8.

So when you put it in expanded form, you get 2000+50+8

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Help!!!!!!!!!!! !!!!!
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A point charge q1 = -2.1 ?C is located at the origin of a co-ordinate system. Another point charge q2 = 6.7 ?C is located along
larisa [96]
Answer 1
 By definition of the coulomb law we have that the force between two charges is given by
 F12 = K (q1 * q2) / (r ^ 2)
 where
 K = 9 * 10 ^ 9 [N.m ^ 2 / C ^ 2] (constant)
 q1 = load 1 [C]
 q2 = load 2 [C]
 r = distance between charges [m]
 Substituting the values we have
 F12 = (9000000000) * ((- 2.10E-06) * (6.70E-06) / ((0.067) ^ 2))
 F12 = -28.2N
 
 answer 2

 In this case the value of r will be given by
 ROOT ((0.067) ^ 2 + (0.028) ^ 2) = 0.0726 m
 Then, the net force will be given by
 F12 = (9000000000) * ((- 2.10E-06) * (6.70E-06) / ((0.0726) ^ 2))
 F12 = -24.01
 The horizontal component of this force is
 F12x = F12 (x / r) = - 24.01 (0.067 / 0.072)
 F12x = -22.2N
 The answer is -22.2N


 answer 3
 For this case we have by sum of forces that
 F2N = F12 + F32
 where
 F2N = 8,005 N
 F12 = -24.01 N
 Clearing F32
 F32 = F2N + F12 = (8.005) - (- 24.01) = 32.01N
 Then, by definition
 F32 = K (q2 * q3) / (r ^ 2)
 clearing q3
 q3 = (F32 (r ^ 2)) / (K * q2)
 substituting
 q3 = ((32.01) ((0.0726 / 2) ^ 2)) / ((9000000000) * (6.70E-06))
 q3 = 1.4E-06 C
 the answer is 1.4E-06 C (+)
4 0
4 years ago
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