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irina1246 [14]
3 years ago
11

5

Mathematics
1 answer:
sashaice [31]3 years ago
6 0

Answer:

An 8-pack of frozen waffles costs $6.91. What is the unit price, rounded to the nearest cent?

Step-by-step explanation:

it is jashdsdhkjasdhjsd

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Eya is 5 years younger than 3 times Bills age. If Eya is 28 how old is Bill?
Sedaia [141]
Bill's age = x

Eya's age = 3x - 5

Eya is 28

28 = 3x - 5

28 (+5) = 3x -5 (+5)

33 = 3x

33/3 = 3x/3

x = 11

Bill = x

x = 11

Bill is 11 years old

hope this helps
4 0
4 years ago
A telephone pole has a wire to its top that is anchored to the ground. The distance from the bottom of the pole to the anchor po
Bumek [7]

Answer:

The height of the pole is 105ft,

Step-by-step explanation:

Let us call h the height of the pole, then we know that the distance from the bottom of the pole to the anchor point is 49, or it is h - 49.

The wire length d is 14 ft longer than height h, hence

d= h+14.

Thus we get a right triangle with hypotenuse d= y+14, perpendicular  h, and base h-49; therefore, the Pythagorean theorem gives

(h-49)^2+h^2 = (h+14)^2

which upon expanding we get:

h^2-98h+2401 = h^2+28h+196

further simplification gives

h^2-126h+2205=0,

which is a quadratic equation with solutions

h =21ft\\h = 105ft.

Since the first solution h =21ft will give the triangle base length of 21ft-49ft = -28ft which is negative; therefore, we disregard it and pick the solution h = 105ft.

Hence, the height of the pole is 105ft.

3 0
3 years ago
Dividing three didget numbers
nika2105 [10]
Where is the work????????????
7 0
3 years ago
What is the answer P=4x+qx-5
Nastasia [14]

p=qx+4x−5 would be the answer to your problem. Math Papa is a good website to use for alegebra or math



8 0
3 years ago
Read 2 more answers
You have been provided with the following logic
amid [387]

If X and Y are Boolean variables, then X + Y represents disjunction (OR) and XY represents conjunction (AND), and X' denotes the negation (NOT). So X + Y = 1 if either X = 1 or Y = 1, and XY = 1 only if both X = 1 or Y = 1.

Now,

(X + Y) (X + Y') = XX + YX + XY' + YY'

… = X + X (Y + Y') + 0

… = X + X

… = X

or in table form,

\begin{array}{c|cccc}X&1&1&0&0\\Y&1&0&1&0\\Y'&0&1&0&1\\X+Y&1&1&1&0\\X+Y'&1&1&0&1\\(X+Y)(X+Y')&1&1&0&0\end{array}

5 0
3 years ago
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