Step-by-step explanation:
Let ABCD be a rhombus. So, AC (AC = 14 cm) and BD (BD=48 cm) will be its diagonals. Let us assume that diagonals are intersecting at point O.
Since, diagonals of a rhombus are perpendicular bisector.
Hence, length of a side (or all) is 25 cm.
Answer:
F(1)= (1)2 + 2
2+2
=4
F(5)= (5)2 + 2
10+2
=12
F(1) + F(5) = 12+4
=16
Step-by-step explanation:
:D
Answer:
n=10
Step-by-step explanation:
2^(n+2)=2^12
n+2=12
n=10
Answer:
( d / c ) < ( a / d )
( b / d ) < ( a / d )
( d / a ) < ( a / d )
Step-by-step explanation:
For this problem, we need to consider the given information that a > b > c > d > 0. Note that a is the greatest number and that d is the least number.
Given this fact, we can create a fraction that will result in a maximum value by simply doing the following:
a / d
The reason the fraction ( a / d ) results in a maximum, is because of the given information where a is the furthest from 0, and d is the closest to 0. Therefore, we can say that no other combination will result in a value greater than ( a / d).
So in the three given statements, we have different combinations of fractions being compared to our maximum value fraction. Our maximum value fraction ( a / d ) will always be greater than any other combination.
Thus, we will choose the sign that makes ( a / d ) greater than the other choice fractions.
Cheers.
